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17 Jun 2018, 06:27
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
84% (00:54) correct
16%
(01:29)
wrong
based on 140
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Is \(ax = \frac{(7 + 5bx)}{4}\) ?
(1) \(x(4a - 5b) = 7\)
(2) \(a = 1\)
(1) \(x(4a - 5b) = 7\)
(2) \(a = 1\)
17 Jun 2018, 07:37
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\(ax = \frac{(7 + 5bx)}{4}\)
\(4ax = (7 + 5bx)\)
\(4ax -5bx=7\)
\(x(4a -5b)=7\)
(1) \(x(4a - 5b) = 7\). Sufficient
(2) \(a = 1\). Not Sufficient (this statement tells us nothing about b)
Answer A.
\(4ax = (7 + 5bx)\)
\(4ax -5bx=7\)
\(x(4a -5b)=7\)
(1) \(x(4a - 5b) = 7\). Sufficient
(2) \(a = 1\). Not Sufficient (this statement tells us nothing about b)
Answer A.
19 Jun 2018, 00:23
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Bunuel
Is \(ax = \frac{(7 + 5bx)}{4}\) ?
(1) \(x(4a - 5b) = 7\)
(2) \(a = 1\)
(1) \(x(4a - 5b) = 7\)
(2) \(a = 1\)
Given ,
ax=\(\frac{(7+5bx)}{4}\)
4ax = (7+5bx)
4ax-5bx=7
x(4a-5b)=7...............................1
Statement 1: The same as equation 1. Sufficient.
Statement 2: a =1. we don't know the value of b. Not sufficient.
Thus A is the best answer.
