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Himalayan
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kirakira
Himalayan
Is (E!+Q!)! even?

(1) E=Q
(2) Q=2

(A) it is

(2) Q = 2 but E can be 1 => E! + Q! = odd => insuff



(2) is sufficient I guess you missed one more factorial (E!+Q!)!

(1!+2!)!=3!=6 even
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Sergey_is_cool
kirakira
Himalayan
Is (E!+Q!)! even?

(1) E=Q
(2) Q=2

(A) it is

(2) Q = 2 but E can be 1 => E! + Q! = odd => insuff


(2) is sufficient I guess you missed one more factorial (E!+Q!)!

(1!+2!)!=3!=6 even


Yeah, I missed it. Thanks :)
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Sergey_is_cool
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Happens to me all the time :)
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Himalayan
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Sergey_is_cool
Happens to me all the time :)


happens to everybody. :lol:


it happens more, the more one learns.
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sankha
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(E! + Q!)! will always be even. Let me prove this. The smallest sum of E! and Q! is 2. Any sum greater than 2 will produce a factorial which is even.

I dont understand the question. Is it even correct?
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Fig
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(C) for me :)

(E!+Q!)! even ?

We have first to know if E & Q are integers and in addition positive ! :)

From 1
E=Q... Nothing is said about E & Q positive integers

INSUFF.

From 2
Q=2... what about E ? A positive integer?

INSUFF.

Combining (1) & (2)
Ok... Now we have E=Q=2.... 2+2=4... Even

SUFF.
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Dek
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I got D.

What is the OA on this one. Do we always assume that if it doesnt say integer it isnt. And what is -3! !!
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Dek
I got D.

What is the OA on this one. Do we always assume that if it doesnt say integer it isnt. And what is -3! !!


We never can assume that we have an integer. Indeed, it needs to be stated. :)
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Is answer C ? btw what is the factorial of a negative integer?
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Himalayan
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abhinava
Is answer C ? btw what is the factorial of a negative integer?


negatives do not have any factorial. but 0 has.

0! = 1! = 1



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