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Bunuel
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Statement 1 : f<g+1
For this equation lets take following values of f & g and test if f < g
f = 2 g = 2 f is not less than g
f = 2 g = 3 f i s less than g

Insufficient



Statement 2:
|f|/|g| <1
this means |g|>|f|
In sufficient

1+2 statements;

f< g
sufficient
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MarkusKarl
(1) the difference between f and g could be less than 1, thus we cannot determinate if f < g.
(2) abs of f is smaller than abs of g. f could be positive 2 and g could be -3 or 3. Ns.

(1+2)
not sufficient.
F = 10 g= 12 => fF=,3 g=-,6 f>g

Any other approaches for 1+2?

Ill Go with E
Posted from my mobile device

Posted from my mobile device

With your example,

F=,3 g=-,6 --> Statement 1 is not getting satisfied. Hence, this example is invalid.
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abhimahna
MarkusKarl
(1) the difference between f and g could be less than 1, thus we cannot determinate if f < g.
(2) abs of f is smaller than abs of g. f could be positive 2 and g could be -3 or 3. Ns.

(1+2)
not sufficient.
F = 10 g= 12 => fF=,3 g=-,6 f>g

Any other approaches for 1+2?

Ill Go with E
Posted from my mobile device

Posted from my mobile device

With your example,

F=,3 g=-,6 --> Statement 1 is not getting satisfied. Hence, this example is invalid.

-,6+1=,4>,3

What am I missing? :/
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MarkusKarl
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(1) the difference between f and g could be less than 1, thus we cannot determinate if f < g.
(2) abs of f is smaller than abs of g. f could be positive 2 and g could be -3 or 3. Ns.

(1+2)
not sufficient.
F = 10 g= 12 => fF=,3 g=-,6 f>g

Any other approaches for 1+2?

Ill Go with E
Posted from my mobile device

Posted from my mobile device

With your example,

F=,3 g=-,6 --> Statement 1 is not getting satisfied. Hence, this example is invalid.

-,6+1=,4>,3

What am I missing? :/

You have taken f = 3 and g =-6.

Statement 1 says f < g+1.

as per your example, we are getting 3 < -6+1

or 3<-5 which is NOT true. hence, its an invalid example.
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I could have been clearer.
F=0.3
G=-0.6

Posted from my mobile device
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MarkusKarl
I could have been clearer.
F=0.3
G=-0.6

Posted from my mobile device

Yes, I believe I missed this condition. yes, you are right. Answer should be E.

Thanks Mate. :)
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MarkusKarl
I could have been clearer.
F=0.3
G=-0.6

Posted from my mobile device

Yes, I believe I missed this condition. yes, you are right. Answer should be E.

Thanks Mate. :)

My bad for not writing the numbers properly :)

Posted from my mobile device
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Bunuel
Is f < g?

(1) f < g + 1
(2) |f|/|g| < 1

Q: is f-g < 0

1) f < g+1 => f-g<1, not sufficient.

2) |f| / |g| < 1, that means |g| > |f|, not sufficient as g can be -4 and f can -3 => f>g

1 + 2,

f < g +1
|f| < |g|

that means g has to be +2 > f so that above two statments work

answer is C
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Bunuel, Sir, Please guide. According to me the answer is C...I donot understand how is OA E?
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Is f < g?

(1) f < g + 1
(2) |f|/|g| < 1

Bunuel, Sir, Please guide. According to me the answer is C...I donot understand how is OA E?

Why do you think the answer is C? How did you get it? If you check the discussion above you'll find the examples proving that the answer is indeed E.

If f = 0.3 and g = -0.6, then the answer is NO.
If f = 1 and g = 2, then the answer is YES.
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Thanks a lot Bunuel Sir for your time and explanation :) I missed to take into account decimals.. Will be careful next time.
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Bunuel
Is f < g?

(1) f < g + 1
(2) |f|/|g| < 1

We need to determine whether f < g.

Statement One Alone:

f < g + 1

Statement one alone is not sufficient to answer the question. For instance, if f = 2 and g = 2, then f IS NOT less than g. However, if f = 1 and g = 2, then f IS less than g.

Statement Two Alone:

|f|/|g| < 1

We can multiply both sides of the inequality by |g| to get:

|f| < |g|

We can also determine that statement two alone is not sufficient to answer the question.

For instance, if f = -1 and g = -2, then f IS NOT less than g. However, if f = 1 and g = 2, then f IS less than g.

Statements One and Two Together:

Using the information from statements one and two, we know that f < g + 1 and that |f| < |g|. This is still not enough information to answer the question.

For instance, if f = -1 and g = -1.75, then f IS NOT less than g. However, if f = 1 and g = 2, then f IS less than g.

Answer: E
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