Is g

Question

Is  g< g^2 < g^3 , for all real values of  g ?

(1)  g < g^3 
(2)  g^3 > g^2

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chetan2u · Answer

What can we make out of gg^2 or c) g cannot be less than or equal to 1 as the number becomes lesser as the power increases. Thus we are looking at whether g>1. (1) g < g^3 If g is positive, then surely g>1. If g is negative and >-1, then surely g<1. So not sufficient OR g^3-g>0.......g(g^2-1)>0 Case I g>0, then g^2-1>0 or g>1.....Yes, g is greater than 1. Case II g<0, then g^2-1<0......g^2<1......-1 g^2 g^3-g^2>0.......g^2(g-1)>0 Only one case possible as g^2 >0. Thus, g-1>0 or g>1.....Yes, g is greater than 1. When a number greater than 1 is raised to higher powers, the value becomes greater , that is => g^3>g^2>g Sufficient B

TarunKumar1234 · Answer

Is g< g^2 < g^3, for all real values of g?
It will be true if g>1.

Stat1: g < g^3
g*(g^2 - 1) >0 or, g<-1 or g>1, so, g^2>g >g^3 or, g< g^2 < g^3. Not sufficient.

Stat2: g^3 > g^2
g^2 *(g-1)>0 or, g>1, so, g< g^2 < g^3. Sufficient.

So, I think B.

GCMEMBER · Answer

Is g < g^2 < g^3, for all real values of g? (1) g < g^3 g(g^2 - 1)>0 So, -11 For -1 g^2 g^2(g-1)>0 So, g>1 For g>1, g< g^2 < g^3. Sufficient. Option B Posted from my mobile device

dimdiak · Answer

Statement 1is not suff because g can be either integer or franction. Therefore is not clear to answer.

Statement 2 tell us that variable g is an integer thus we can answer

IMO B

Nidhijain94 · Answer

How can this be the case? the statement itself says g^3> g . I think you wanted to say g^2>g^3>g. if g >1 then g^3>g^2>g and if -1g^3>g. So, not sufficient

DHRJ0032 · Answer

B is the answer.

Posted from my mobile device

Is g < g^2 < g^3, for all real values of g?

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