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Is G>H ?

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Is G>H ?  [#permalink]

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New post 09 Apr 2016, 22:07
1
3
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

79% (00:59) correct 21% (00:58) wrong based on 62 sessions

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Is G>H ?  [#permalink]

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New post 09 Apr 2016, 22:30
1
St1: G - 5 > H - 5 --> Clearly sufficient to prove G > H

St2: G^2 - GH > 0
G^2 is positive --> G can be negative or positive
Suppose the value of GH is negative --> If G is positive and H is negative then G > H
If G is negative and H is positive then G < H
Not Sufficient

Answer: A

Edited the solution
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Re: Is G>H ?  [#permalink]

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New post 27 May 2016, 05:04
Vyshak wrote:
St1: G - 5 > H - 5 --> Clearly sufficient to prove G > H

St2: G(G - H) > 0 --> G > 0 or G > H
If G > 0; H can be 0 and G(G - H) > 0 --> In this case is G > H? No
Not Sufficient

Answer: A


Hi, thank you for your explanation. Here, the question asks whether G>H
In statement 2, the inequality clearly satisfies this condition. l am not clear why its still insufficient.
Help? :oops:
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Re: Is G>H ?  [#permalink]

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New post 27 May 2016, 05:27
1
ranaazad wrote:
Vyshak wrote:
St1: G - 5 > H - 5 --> Clearly sufficient to prove G > H

St2: G(G - H) > 0 --> G > 0 or G > H
If G > 0; H can be 0 and G(G - H) > 0 --> In this case is G > H? No
Not Sufficient

Answer: A


Hi, thank you for your explanation. Here, the question asks whether G>H
In statement 2, the inequality clearly satisfies this condition. l am not clear why its still insufficient.
Help? :oops:


Hi,

I am not able to understand my own explanation for the 2nd statement. I will edit my solution.

Please refer to the below explanation for the 2nd statement:

G^2 - GH > 0
G^2 is positive --> G can be negative or positive
Suppose the value of GH is negative --> If G is positive and H is negative then G > H
If G is negative and H is positive then G < H
Not Sufficient
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Re: Is G>H ?  [#permalink]

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New post 27 May 2016, 05:44
stonecold wrote:
Is G>H ?
[A] G-5>H-5
G^2>GH


[b] Statement 1

G-5 > H -5
We can remove 5 from both sides.

G > H.

Statement 1 is sufficient

Statement 2

\(G^2\)>GH

G.G>G.H
G(G-H) > 0

Either G < 0 or G > H

Not sufficient

Answer: Option A
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Re: Is G>H ?  [#permalink]

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New post 28 May 2016, 12:40
For statement 2,
G^2>GH

Since no information is given about G, we will consider two cases for G,
1.) When G is +ve, then (G^2)/G>(GH)/G --------> G>H

2.)When G is -ve, then (G^2)/(-G)<(GH)/(-G) ------------> G<H because, when an inequality is divided by a -ve number then sign of inequality changes.

Therefore, statement 2 is insufficient.

Hence, answer will be A.
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Re: Is G>H ?  [#permalink]

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New post 03 Sep 2018, 06:51
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Is G>H ? &nbs [#permalink] 03 Sep 2018, 06:51
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