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# Is lxl < 1? (1) lx + 1l = 2 lx - 1l (2) lx - 3l 0 A.

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Intern
Joined: 08 Nov 2008
Posts: 38
Is lxl < 1? (1) lx + 1l = 2 lx - 1l (2) lx - 3l 0 A. [#permalink]

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09 Nov 2008, 18:19
Is lxl < 1?

(1) lx + 1l = 2 lx - 1l
(2) lx - 3l ≠ 0

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

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09 Nov 2008, 21:30
gorden wrote:
Is lxl < 1?

(1) lx + 1l = 2 lx - 1l
(2) lx - 3l ≠ 0

1: lx + 1l = 2 lx - 1l
if lx + 1l and 2 lx - 1l are +ve.
x + 1 = 2x - 2
x = 3

if either lx + 1l (or lx - 1l) is -ve.
x + 1 = -2x +1
x = 0
nsf..

(2) if lx - 3l ≠ 0, x is not 3.

nsf.

1 & 2: x = 0. suff..

C.

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Re: absolute value---28   [#permalink] 09 Nov 2008, 21:30
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# Is lxl < 1? (1) lx + 1l = 2 lx - 1l (2) lx - 3l 0 A.

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