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25 Jul 2009, 04:16
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Is m>0?
1. m^2/-3 0
Stmt 1..m^2/-3 0. So m>0 . Suff.
Where did I go wrong guys?
1. m^2/-3 0
Stmt 1..m^2/-3 0. So m>0 . Suff.
Where did I go wrong guys?
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
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25 Jul 2009, 04:43
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[quote="tejal777"]Is m>0?
1. m^2/-3 <0
2. (-m)(-5) >0
from 1
m^2 is +ve >0 still we cant know whether m is +ve or -ve
from 2
5m>0 m is +ve...............suff
B
1. m^2/-3 <0
2. (-m)(-5) >0
from 1
m^2 is +ve >0 still we cant know whether m is +ve or -ve
from 2
5m>0 m is +ve...............suff
B
25 Jul 2009, 06:54
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tejal777
Answer should be B for sure this time
The statement in RED is partially correct...m^2 < 0 implies that m is a fraction between -1 and 1. But which kind of fraction ? +ve or -ve ?
eg. (0.50)^2 is less than 0.
Also ( -0.50 )^2 is less than 0.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
