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Is m>0? 1. m^2/-3 <0 2. (-m)(-5) >0 Stmt 1..m^2/-3

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Director
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Joined: 25 Oct 2008
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Location: Kolkata,India
Is m>0? 1. m^2/-3 <0 2. (-m)(-5) >0 Stmt 1..m^2/-3 [#permalink]

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New post 25 Jul 2009, 04:16
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A
B
C
D
E

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Is m>0?
1. m^2/-3 <0
2. (-m)(-5) >0

Stmt 1..m^2/-3 <0
m^2<0...this is only possible when m is a fraction.Therefore suff.

stmt 2.. 5m>0. So m>0 . Suff.

Where did I go wrong guys?
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http://gmatclub.com/forum/countdown-beginshas-ended-85483-40.html#p649902

Kudos [?]: 1143 [0], given: 100

SVP
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B
Joined: 05 Jul 2006
Posts: 1751

Kudos [?]: 432 [0], given: 49

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Re: Is m>0? [#permalink]

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New post 25 Jul 2009, 04:43
[quote="tejal777"]Is m>0?
1. m^2/-3 <0
2. (-m)(-5) >0

from 1

m^2 is +ve >0 still we cant know whether m is +ve or -ve

from 2

5m>0 m is +ve...............suff

B

Kudos [?]: 432 [0], given: 49

Director
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Joined: 01 Apr 2008
Posts: 873

Kudos [?]: 844 [0], given: 18

Name: Ronak Amin
Schools: IIM Lucknow (IPMX) - Class of 2014
Re: Is m>0? [#permalink]

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New post 25 Jul 2009, 06:54
tejal777 wrote:
Stmt 1..m^2/-3 <0
m^2<0...this is only possible when m is a fraction.Therefore suff.
Where did I go wrong guys?

Answer should be B for sure this time :)

The statement in RED is partially correct...m^2 < 0 implies that m is a fraction between -1 and 1. But which kind of fraction ? +ve or -ve ?
eg. (0.50)^2 is less than 0.
Also ( -0.50 )^2 is less than 0.

Kudos [?]: 844 [0], given: 18

Re: Is m>0?   [#permalink] 25 Jul 2009, 06:54
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