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Is √p a non-integer? (1) p = r × 10 r, where r is a positive odd in

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Is √p a non-integer? (1) p = r × 10 r, where r is a positive odd in [#permalink]

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New post 23 Mar 2017, 18:11
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Is \(√p\) a non-integer?

(1) \(p = r × 10^r\), where r is a positive odd integer.
(2) \(p = 9 × 10^s\), where s is a positive integer.
[Reveal] Spoiler: OA

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Re: Is √p a non-integer? (1) p = r × 10 r, where r is a positive odd in [#permalink]

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New post 23 Mar 2017, 19:10
avinsethi wrote:
A?

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Yes its A...

(1) 10^odd integer is never a square .
HEre r is odd integer.

suff.

(2) we dont have enough info of s (even /odd).
if s=even then YES
if s=odd then NO
insuff

Ans A

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Is √p a non-integer? (1) p = r × 10 r, where r is a positive odd in [#permalink]

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New post 23 Mar 2017, 19:20
Is \(√p\) a non-integer?

(1) \(p = r × 10^r\), where r is a positive odd integer.

Let r= 1..........\(√10\)...........Answer is yes

Let r= 3..........\(√10^3\)...........Answer is yes

Any ODD power will yield always NON-Integer number

Sufficient

(2) \(p = 9 × 10^s\), where s is a positive integer.

Let s= 1..........\(√9*10\)...........Answer is yes

Let s= 2..........\(√9*10^2\)...........Answer is No

Insufficient

Answer A

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Re: Is √p a non-integer? (1) p = r × 10 r, where r is a positive odd in [#permalink]

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New post 25 Sep 2017, 18:17
hazelnut wrote:
Is \(√p\) a non-integer?

(1) \(p = r × 10^r\), where r is a positive odd integer.
(2) \(p = 9 × 10^s\), where s is a positive integer.


Statement 1

In order for the square root of p to be an integer there must be an even number of exponents in the factors of p squared- for example

100 = 5^2 * 2^2
64= 2^6
9= 3^2


suff

Statement 2

Too many possibilities- it is not known whether or not s is odd

insuff

A

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Re: Is √p a non-integer? (1) p = r × 10 r, where r is a positive odd in   [#permalink] 25 Sep 2017, 18:17
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Is √p a non-integer? (1) p = r × 10 r, where r is a positive odd in

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