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14 Jul 2018, 02:37
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Hi chetan2u
The question can be simplified into either (1) or (2)
In 2, on simplification, we get 2pq+p² <0
Using statement 1 of the question, we can not prove this as sufficient
That is my question
Also, as stated by you "2pq+p^2<0
p^2 is surely positive so 2pq<0
This means - are p AND q of different sign"
this is simplified into 2pq<-p^2 and not otherwise as stated by you.
Posted from my mobile device
The question can be simplified into either (1) or (2)
In 2, on simplification, we get 2pq+p² <0
Using statement 1 of the question, we can not prove this as sufficient
That is my question
Also, as stated by you "2pq+p^2<0
p^2 is surely positive so 2pq<0
This means - are p AND q of different sign"
this is simplified into 2pq<-p^2 and not otherwise as stated by you.
Posted from my mobile device
13 May 2019, 00:05
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chetan2u
I appreciate your skills. Could you please explain how have you zeroed in on conclusion that solely q=0 is all what we have to keep in mind? I got lost in thinking whether + n - cases and also whether p n q are between 0 n 1.
14 May 2019, 03:22
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Bunuel
So this is how i went about it.
|qp+q^2| > qp
=> qp+q^2 > qp ------(1)
or
qp+q^2 < -qp -----(2)
from 1,we get
q>0 or q<0 -----(3)
or
from 2, we get
q>0 and q/p > -2 -----(4)
or
q<0 and q/p < -2 -----(5)
stmt 1 says: q>o
This is what we get from (3). so stmt 1 is sufficient.
stmt 2 says: q/p > 1
from (4), we really can say that the problem statement is true
from (5), we can say that the problem statement is false.
Since, there is a 'or' between (4) and (5), stmt 2 is sufficient as well.
so Ans is D Bunuel or chetan2u , can either of you please tell me if my analysis is correct?
