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chunjuwu
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crackgmat3
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hardworker_indian
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wireless_neo
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Agree with crackgmat.
Ans should be E.
Hardworker, your answer is B. But, according to second condition the quadrilateral can be a square, rectangle or a rhombus.
According to first condition, the quadrilateral can be a square or a rectangle.
I think answer should be E
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lastochka
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I think the answer is B
try having two diagonals which are EQUAL in length and BISECT each other. You will inevitably result with a rectangle. Correct me if i'm wrong.

OA please?
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jinino
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My answer is B. Two diagonals are equal and bisect to each other will give
you a square, and somewhere in my memory tells me all squares are
also retangulars.

Need OA.
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jinino
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My answer is B. Two diagonals are equal and bisect to each other will give
you a square, and somewhere in my memory tells me all squares are
also retangulars.

Need OA.
guest55
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two diagonals that are equal and bisect each other don't give a square but a rectangle. if they are perpendicular and equal we have a square. ans B.
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PracticeMore
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I will go by B . A square is a subset of a Rectangle.
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vivek.173
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i also agree with B.
Simple rule : All squares are rectangle,but not necessarily that all rectangles are square.

Condition 1st doesn't reveal if it's a rectangle but codition 2nd clearly says its a square..
Hence B
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mbahope
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I'd go with D.
Whats the OA please?
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gmatmath
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I'll go with E. (Initially I thought C. )

1. => All 4 angles are 90 degree angles.
2. => Can be a square or Rectangle.
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Praetorian
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This was posted a month and a half ago, i will have to pm the author ..lets see

Praetorian



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