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Is the integer n a multiple of 15? 1) n is a muliple of 20

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Manager
Joined: 17 Aug 2006
Posts: 86
Is the integer n a multiple of 15? 1) n is a muliple of 20 [#permalink]

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13 Nov 2008, 05:30
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is the integer n a multiple of 15?

1) n is a muliple of 20

2) n +6 is a multiple of 3
SVP
Joined: 17 Jun 2008
Posts: 1504
Re: PROB PREP 8 OF 37 [#permalink]

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13 Nov 2008, 05:57
C.

From stmt1: n has 5 as one of the factors.
From stmt2: n has 3 as one of the factors.

Combining both, n is divisible by 15.
Senior Manager
Joined: 21 Apr 2008
Posts: 265
Location: Motortown
Re: PROB PREP 8 OF 37 [#permalink]

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13 Nov 2008, 07:12
scthakur wrote:
C.

From stmt1: n has 5 as one of the factors.
From stmt2: n has 3 as one of the factors.

Combining both, n is divisible by 15.

agreed
Manager
Joined: 23 Jul 2008
Posts: 189
Re: PROB PREP 8 OF 37 [#permalink]

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13 Nov 2008, 12:30
1) n= 20,40,60,80,100,120 and so on may be may be not
2)n=0,3,6,9,12,15 and so on again may be may be not
combining possible values of n= 60,120,180 divisibility by 15 yes
IMO C
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Joined: 18 Jul 2008
Posts: 920
Re: PROB PREP 8 OF 37 [#permalink]

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30 Nov 2008, 21:33
That's the answer I got, but I ended plugging in numbers. Can you explain your method? I need help on factoring.

scthakur wrote:
C.

From stmt1: n has 5 as one of the factors.
From stmt2: n has 3 as one of the factors.

Combining both, n is divisible by 15.
Director
Joined: 14 Aug 2007
Posts: 704
Re: PROB PREP 8 OF 37 [#permalink]

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30 Nov 2008, 23:20
1
KUDOS
That's the answer I got, but I ended plugging in numbers. Can you explain your method? I need help on factoring.

scthakur wrote:
C.

From stmt1: n has 5 as one of the factors.
From stmt2: n has 3 as one of the factors.

Combining both, n is divisible by 15.

we have to find if n is divisible by 15 or not.

for a number to be divisible by 15 it needs 3*5 as factors.

1) tells us that 5*4 are factors (but no 3)
2) tells us that 3 is a factor. (but no 5)

together we know that 5*3 both are factors
Current Student
Joined: 28 Dec 2004
Posts: 3312
Location: New York City
Schools: Wharton'11 HBS'12
Re: PROB PREP 8 OF 37 [#permalink]

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01 Dec 2008, 15:10
i get C too...here is how.

stmnt 2 says n-6=3M so n=3m-6 or n=3(M-2) where M is some integer

n/3= m-2 or some integer..so N must be a mutiple of 3 ..stmnt says n is also multiple of 5
Re: PROB PREP 8 OF 37   [#permalink] 01 Dec 2008, 15:10
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Is the integer n a multiple of 15? 1) n is a muliple of 20

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