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anuramm
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Alex_NL
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stuti
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It would be best to take numbers.
1. lets take (3,-4) and (-4,-5) - which is a line that's in the III and IV th quadrant. Slope = (y1-y2)/(x1-x2) = (-5+4)/(3+4) which is <0. However if the co-ordinates are (3,-2) and (-4,-5) the slope is >0. So, Insufficient.

2. Lets take (3,4) and (-4,-5) - which is a line that's in the Ist and IVth quadrant. Slope will be (4+5)/(3+4) >0 and will always be >0. So, Sufficient.

Ans is B.
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stuti
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venksune
It would be best to take numbers.
1. lets take (3,-4) and (-4,-5) - which is a line that's in the III and IV th quadrant. Slope = (y1-y2)/(x1-x2) = (-5+4)/(3+4) which is <0. However if the co-ordinates are (3,-2) and (-4,-5) the slope is >0. So, Insufficient.

2. Lets take (3,4) and (-4,-5) - which is a line that's in the Ist and IVth quadrant. Slope will be (4+5)/(3+4) >0 and will always be >0. So, Sufficient.

Ans is B.


Its B - didnt consider the other case :oops:
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Alex_NL
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Isnt (-4, -5) not in the third quadrant.

I assume that
(4, 5) 1st quadrant
(-4, 5) 2nd quadrant
(-4, -5) 3rd quadrant
(4, -5) 4th quadrant.

Please correct me if I am wrong.

Regards,

Alex
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venksune
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Oh Oh... thanks for pointing out Alex, my mistake...took the wrong values for the quadrants...let me do this again...


1. lets take (-3,-4) and (4,-5) - which is a line that's in the III and IV th quadrant. Slope = (y1-y2)/(x1-x2) = (-4+5)/(-3+4) which is >0. However if the co-ordinates are (-6,-4) and (4,-5) the slope is (-4+5)/(-6-4) which is 0 . Also the slope of the line could be 0.

Combining both we have slope of line = 0 which is not >0. Hence C.



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