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02 Jan 2004, 19:21
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Is the two-digit integer, with digits R and M (in that order), a multiple of 7?
(1) R + M = 13
(2) R is divisible by 3
(1) R + M = 13
(2) R is divisible by 3
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02 Jan 2004, 21:31
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1 is sufficient.
MR = 49/7
M+R=13
The only other options M+R = 13 are 67, 58, 94, 85, 76 none are divisile y 7
2 is extra statement
1 is sufficient.
MR = 49/7
M+R=13
The only other options M+R = 13 are 67, 58, 94, 85, 76 none are divisile y 7
2 is extra statement
03 Jan 2004, 07:40
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C as well. 1 is not sufficient on it's own. True that 49 is divisible by 13 but so is 58 and the latter is not a multiple of 7. Both statements combined say that RM is definitely not a multiple of 7
