GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 17 Oct 2019, 16:50

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Is x < 0? (1) x^3 + 8 < 0 (2) -(x/4 + 3) > 0

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 58402
Is x < 0? (1) x^3 + 8 < 0 (2) -(x/4 + 3) > 0  [#permalink]

### Show Tags

02 Apr 2018, 21:51
00:00

Difficulty:

25% (medium)

Question Stats:

88% (01:10) correct 13% (01:18) wrong based on 36 sessions

### HideShow timer Statistics

Is $$x < 0$$?

(1) $$x^3 + 8 < 0$$

(2) $$-(\frac{x}{4} + 3) > 0$$

_________________
Intern
Joined: 28 Apr 2014
Posts: 49
GMAT 1: 640 Q50 V25
Re: Is x < 0? (1) x^3 + 8 < 0 (2) -(x/4 + 3) > 0  [#permalink]

### Show Tags

02 Apr 2018, 22:30
IMO D

St1
x^3<-8
x<-2
sufficient

St2
x/4+3<0
x<-12
sufficient
examPAL Representative
Joined: 07 Dec 2017
Posts: 1140
Re: Is x < 0? (1) x^3 + 8 < 0 (2) -(x/4 + 3) > 0  [#permalink]

### Show Tags

02 Apr 2018, 23:05
Bunuel wrote:
Is $$x < 0$$?

(1) $$x^3 + 8 < 0$$

(2) $$-(\frac{x}{4} + 3) > 0$$

As we're asked about a number property (positive/negative) we'll look for a property based solution.
This is a Logical approach.

(1) If x is positive or zero, then x^3 is positive or zero and x^3 + 8 is positive, in contradiction to the statement.
Then x must be negative.
Sufficient.

(2) If x is positive or zero, then x/4+3 is positive or zero and -(x/4+3) is negative or zero, in contradiction to the statement.
Then x must be negative.
Sufficient.

_________________
SVP
Joined: 26 Mar 2013
Posts: 2345
Re: Is x < 0? (1) x^3 + 8 < 0 (2) -(x/4 + 3) > 0  [#permalink]

### Show Tags

03 Apr 2018, 16:47
1
Bunuel wrote:
Is $$x < 0$$?

(1) $$x^3 + 8 < 0$$

(2) $$-(\frac{x}{4} + 3) > 0$$

(1) $$x^3 + 8 < 0$$

$$x^3 < -8$$

$$x < -2$$

Hence, x must be negative

Sufficient

(2) $$-(\frac{x}{4} + 3) > 0$$

multiply both sides by -1

$$(\frac{x}{4} + 3) < 0$$

$$\frac{x}{4}< -3$$

$$x < -12$$

Hence, x must be negative

Sufficient

Re: Is x < 0? (1) x^3 + 8 < 0 (2) -(x/4 + 3) > 0   [#permalink] 03 Apr 2018, 16:47
Display posts from previous: Sort by