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# Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3

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Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3  [#permalink]

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Updated on: 07 Apr 2019, 09:58
2
00:00

Difficulty:

25% (medium)

Question Stats:

65% (00:40) correct 35% (00:55) wrong based on 51 sessions

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Is x^2/y < 0 ?

(1) -2 < x < 3

(2) 1 < y < 3

Originally posted by saurabh9gupta on 07 Apr 2019, 09:07.
Last edited by saurabh9gupta on 07 Apr 2019, 09:58, edited 2 times in total.
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Re: Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3  [#permalink]

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07 Apr 2019, 10:01
Taking option B as true, we can clearly say that the expression in the problem would be positive, which gives a definite answer

Posted from my mobile device
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Re: Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3  [#permalink]

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07 Apr 2019, 10:17
Apt0810 wrote:
Taking option B as true, we can clearly say that the expression in the problem would be positive, which gives a definite answer

Posted from my mobile device

from statement 2

X can be 0 also , then

we have 0<0 which is not possible .

Could you help on this whether this reasoning is correct .
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Re: Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3  [#permalink]

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07 Apr 2019, 10:21
m1033512 wrote:
Apt0810 wrote:
Taking option B as true, we can clearly say that the expression in the problem would be positive, which gives a definite answer

Posted from my mobile device

from statement 2

X can be 0 also , then

we have 0<0 which is not possible .

Could you help on this whether this reasoning is correct .

The question asks whether x^2/y < 0.

(2) says that y is positive. Thus, x^2/y is 0, if x = 0, OR positive, if x ≠ 0. In both cases x^2/y is NOT less than 0. So, we have a definite NO answer to the question. That's why (2) is sufficient.

Hope it helps.
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Re: Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3  [#permalink]

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07 Apr 2019, 10:32
Bunuel wrote:
m1033512 wrote:
Apt0810 wrote:
Taking option B as true, we can clearly say that the expression in the problem would be positive, which gives a definite answer

Posted from my mobile device

from statement 2

X can be 0 also , then

we have 0<0 which is not possible .

Could you help on this whether this reasoning is correct .

The question asks whether x^2/y < 0.

(2) says that y is positive. Thus, x^2/y is 0, if x = 0, OR positive, if x ≠ 0. In both cases x^2/y is NOT less than 0. So, we have a definite NO answer to the question. That's why (2) is sufficient.

Hope it helps.

Got it , Thanks

even if it is 0, we can say it is not less than 0
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Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3  [#permalink]

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07 Apr 2019, 10:52
saurabh9gupta wrote:
Is x^2/y < 0 ?

(1) -2 < x < 3

(2) 1 < y < 3

$$x^2$$ will always be non negative OR

$$x^2 >= 0$$ always.

So now everything comes down to the value of "y"

Statement 1 : $$2 < x < 3$$

If "y" is negative, answer to the question is YES i.e, $$\frac{x^2}{y} < 0$$

but if "y" is positive, answer to the question is NO i.e, $$x^/y$$ not less than "0"

NOT SUFFICIENT

Statement 2 : $$1 < y < 3$$

This shows that $$y > 0$$ always.

Therefore, answer to the question is definite NO. SUFFICIENT

$$\frac{x^2}{y} < 0$$

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Re: Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3  [#permalink]

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07 Apr 2019, 10:55
saurabh9gupta wrote:
Is x^2/y < 0 ?

(1) -2 < x < 3

(2) 1 < y < 3

#1
x would be +ve ; y is not clear
insufficient
#2
y wil be +ve and x whether - pr + no difference it makes
IMO B
Re: Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3   [#permalink] 07 Apr 2019, 10:55
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