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# Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3

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Re: Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3 [#permalink]
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m1033512
Apt0810
Taking option B as true, we can clearly say that the expression in the problem would be positive, which gives a definite answer

Posted from my mobile device

from statement 2

X can be 0 also , then

we have 0<0 which is not possible .

Could you help on this whether this reasoning is correct .

The question asks whether x^2/y < 0.

(2) says that y is positive. Thus, x^2/y is 0, if x = 0, OR positive, if x ≠ 0. In both cases x^2/y is NOT less than 0. So, we have a definite NO answer to the question. That's why (2) is sufficient.

Hope it helps.
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Re: Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3 [#permalink]
Bunuel
m1033512
Apt0810
Taking option B as true, we can clearly say that the expression in the problem would be positive, which gives a definite answer

Posted from my mobile device

from statement 2

X can be 0 also , then

we have 0<0 which is not possible .

Could you help on this whether this reasoning is correct .

The question asks whether x^2/y < 0.

(2) says that y is positive. Thus, x^2/y is 0, if x = 0, OR positive, if x ≠ 0. In both cases x^2/y is NOT less than 0. So, we have a definite NO answer to the question. That's why (2) is sufficient.

Hope it helps.

Got it , Thanks

even if it is 0, we can say it is not less than 0
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Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3 [#permalink]
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saurabh9gupta
Is x^2/y < 0 ?

(1) -2 < x < 3

(2) 1 < y < 3

$$x^2$$ will always be non negative OR

$$x^2 >= 0$$ always.

So now everything comes down to the value of "y"

Statement 1 : $$2 < x < 3$$

No info about "y".

If "y" is negative, answer to the question is YES i.e, $$\frac{x^2}{y} < 0$$

but if "y" is positive, answer to the question is NO i.e, $$x^/y$$ not less than "0"

NOT SUFFICIENT

Statement 2 : $$1 < y < 3$$

This shows that $$y > 0$$ always.

Therefore, answer to the question is definite NO. SUFFICIENT

$$\frac{x^2}{y} < 0$$
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Re: Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3 [#permalink]
saurabh9gupta
Is x^2/y < 0 ?

(1) -2 < x < 3

(2) 1 < y < 3

#1
x would be +ve ; y is not clear
insufficient
#2
y wil be +ve and x whether - pr + no difference it makes
IMO B
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Re: Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3 [#permalink]
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Re: Is x^2/y < 0 ? (1) -2 < x < 3 (2) 1 < y < 3 [#permalink]
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