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20 Mar 2023, 01:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
55% (01:01) correct
45%
(00:56)
wrong
based on 92
sessions
History
Date
Time
Result
Not Attempted Yet
Is x > 3y ?
(1) x/y > 3
(2) y > 7
(1) x/y > 3
(2) y > 7
20 Mar 2023, 02:08
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statement 1 is sufficient
x/y > 3
either both are - or +
multpying y
we get required condition
statement 2
value of x is unknown
insufficient
option A correct
x/y > 3
either both are - or +
multpying y
we get required condition
statement 2
value of x is unknown
insufficient
option A correct
20 Mar 2023, 05:58
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Is x > 3y ?
(1) \(\frac{x}{y} > 3\)
if x=-4 and y=-1 then \(\frac{x}{y}=4>3\) but -4<-3
if x=4 and y=1 then \(\frac{x}{y}=4>3\) but 4>3
Multiple possibilities, thus, insufficient. Eliminate A and D.
(2) y > 7
No information about x. Thus, insufficient. Eliminate B.
(3) \(\frac{x}{y} > 3\) and y > 7
From statement 2 we know y is positive, therefore, now we can multiply by y on both sides of inequality in statement 1 without changing the inequality sign, doing so we get: x>3y. This answers our question. Therefore, C IMO.
(1) \(\frac{x}{y} > 3\)
if x=-4 and y=-1 then \(\frac{x}{y}=4>3\) but -4<-3
if x=4 and y=1 then \(\frac{x}{y}=4>3\) but 4>3
Multiple possibilities, thus, insufficient. Eliminate A and D.
(2) y > 7
No information about x. Thus, insufficient. Eliminate B.
(3) \(\frac{x}{y} > 3\) and y > 7
From statement 2 we know y is positive, therefore, now we can multiply by y on both sides of inequality in statement 1 without changing the inequality sign, doing so we get: x>3y. This answers our question. Therefore, C IMO.
