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Bunuel
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It's a Yes/No Data Sufficiency i.e the options must suggest a bold Yes or a bold No.

1. x^3+x^2=0
=> (x^2)(x+1)=0
We state that either x=0 or x=-1. Not sufficient.

2. x^2+|x|=0
Positive+Positive=0 only when the value is 0.
Hence x is even.

Hence correct answer is B.

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(1) x^3 + x^2 = 0
\(x^2\)(x+1)=0 => \(x^2\)=0 or x+1=0 => x=0 or x=-1
We have 2 values of x. NOT SUFFICIENT

(2)\(x^2\) + |x| = 0
Squaring both sides. \(x^4\)+\(x^2\)=0 => \(x^2\)(\(x^2\)+1)=0 =>\(x^2\)=0 or \(x^2\)=-1(not possible as square root of negative number is an imaginary number) Thus x=0 SUFFICIENT.

IMO answer is option B
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(1) x^3 + x^2 = 0
\(x^2\)(x+1)=0 => \(x^2\)=0 or x+1=0 => x=0 or x=-1
We have 2 values of x. NOT SUFFICIENT

(2)\(x^2\) + |x| = 0
Squaring both sides. \(x^4\)+\(x^2\)=0 => \(x^4\)(\(x^2\)+1)=0 =>\(x^2\)=0 or \(x^2\)=-1(not possible as square root of negative number is an imaginary number) Thus x=0 SUFFICIENT.

IMO answer is option B

you made a mistake here mate: factoring out the x^2, leaves us with x^2(x^2+1)

best gota900
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you made a mistake here mate: factoring out the x^2, leaves us with x^2(x^2+1)

best gota900

Thanks friend. Done.

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Bunuel
Is x an even number?

(1) x^3 + x^2 = 0

(2) x^2 + |x| = 0

Par of GMAT CLUB'S New Year's Quantitative Challenge Set

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Bunuel
Is x an even number?

(1) x^3 + x^2 = 0

(2) x^2 + |x| = 0


But o is neither positive nor negative. So how can we say x is positive ?
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Archit3110
Bunuel
Is x an even number?

(1) x^3 + x^2 = 0

(2) x^2 + |x| = 0


from stmt 1:
x^3 + x^2 = 0
this would be true for x=-1 and 0
not sufficient

from 2:
x^2 + |x| = 0[

when x=0 only possible hence sufficient IMO B

Why is statement 1 not sufficient? The question asks whether x is an even number. I thought neither -1 nor 0 are an even number, so it is sufficient. Could someone please explain why the answer is B and not D?
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philu
Refer below link this may help answer your question related to 0...

https://gmatclub.com/forum/is-zero-even ... 2#p1512948

philu
Archit3110
Bunuel
Is x an even number?

(1) x^3 + x^2 = 0

(2) x^2 + |x| = 0


from stmt 1:
x^3 + x^2 = 0
this would be true for x=-1 and 0
not sufficient

from 2:
x^2 + |x| = 0[

when x=0 only possible hence sufficient IMO B

Why is statement 1 not sufficient? The question asks whether x is an even number. I thought neither -1 nor 0 are an even number, so it is sufficient. Could someone please explain why the answer is B and not D?

Posted from my mobile device
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(1)
\(x^3 + x^2 = 0\)
or, \(x^2(x+1)=0\)
so, x= 0 or -1
Not Sufficient

(2)
\(x^2 + |x| = 0\)
or, x=0
Sufficient

Answer: B
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