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Is x divisible by 9?

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Is x divisible by 9? [#permalink]

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New post 07 Feb 2016, 09:49
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E

Difficulty:

  15% (low)

Question Stats:

74% (00:50) correct 26% (00:34) wrong based on 95 sessions

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Kudos [?]: 139512 [0], given: 12794

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Re: Is x divisible by 9? [#permalink]

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New post 07 Feb 2016, 19:17
Is x divisible by 9 =3^2
that x should have at least 2 factors of 3
(1) x is divisible by 3.
If x= 3 or 6 , then it won't be divisible by 9
If x= 9 or 18 , then it would be divisible by 9
Not sufficient.
(2) When x is divided by 6, the remainder is 3
x= 6n + 3
where n is quotient
If x= 3 , it is not divisible by 9 .
If x=9 , it is divisible by 9.
Not sufficient.
Combining 1 and 2 ,
If x= 3 , it is not divisible by 9 .
If x=9 , it is divisible by 9.
Not sufficient.

Answer E
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Re: Is x divisible by 9? [#permalink]

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New post 16 Mar 2016, 04:13
Nice Question
Here we can see that x=3 and x=9 is satisfied by both the statements
hence E
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Re: Is x divisible by 9? [#permalink]

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New post 18 Dec 2017, 21:57
Bunuel wrote:
Is x divisible by 9?

(1) x is divisible by 3.
(2) When x is divided by 6, the remainder is 3.



(1) A multiple of 3 may or may not be a multiple of 9 (eg, 27 is but 24 is not), so this statement is Insufficient.

(2) x is of the form '6k + 3', where k is a non-negative integer. If we put k=1, we get 9 which is a multiple of 9. But if we put k=2, we get 15 which is not a multiple of 9. So this statement is Insufficient.

Combining the two, a number of the form '6k + 3' is anyway a multiple of 3, and from statement 2 we have seen that this information is not sufficient to know whether the number is divisible by 9 or not. Hence E answer

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Re: Is x divisible by 9?   [#permalink] 18 Dec 2017, 21:57
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