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summer101
Hi Zarrolou,
I thought mod of Zero was illegal.
in (ii) x could be zero. But together we know x cannot be zero hence negative.

Mod of 0 is legit.

\(|0|=0\)
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Zarrolou
Is x negative?

(i) x^2 is a positive number
\(x^2>0\), so \(x\neq{0}\), not sufficient to say that it is negative.

(ii) x * |y| is not a positive number
\(x*|y|\leq{0}\), so y could be 0 and x could have any value (positive, negative, or zero) and this would be respected
Not sufficient.

1+2)Still y could be 0, and in this case x, which now we know cannot be zero, could still equal a positive or negative number.
Example \(2*0\leq{0}\) this respects both conditions and x is positive, or \(-2*0\leq{0}\) here x is negative.
Not sufficient
E

Hi Zarrolou,
I thought mod of Zero was illegal.
in (ii) x could be zero. But together we know x cannot be zero hence negative.
\

|0|=0.

Is x negative?

(1) x^2 is a positive number. This statement implies that \(x\neq{0}\). Not sufficient.

(2) x * |y| is not a positive number --> \(x * |y|\leq{0}\). If \(y=0\), then \(x\) could be ANY number. Not sufficient.

(1)+(2) Again, if \(y=0\), then \(x\) could be ANY number but 0 (excluded because of the first statement). Not sufficient.

Answer: E.
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Is x negative?


(1) x^2 is a positive number

x^2 = +
|x| = +
x could be any number aside from zero and |x| will be positive.
x = positive or negative
INSUFFICIENT

(2) x * |y| is not a positive number
|y| will always be a positive number so for x * |y| to be negative x must be negative.
HOWEVER, the answer could be zero too. 0 is not positive or negative. So, 0 * |y| = 0 OR x * |0| = 0.
x = positive, zero or negative
INSUFFICIENT

1+2) # 1 tells us that x could be positive or negative. # 2 tells us that c could be positive, negative or zero. In other words, x could be positive or negative.
INSUFFICIENT

(E)
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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