summer101
Zarrolou
Is x negative?
(i) x^2 is a positive number
\(x^2>0\), so \(x\neq{0}\), not sufficient to say that it is negative.
(ii) x * |y| is not a positive number
\(x*|y|\leq{0}\), so y could be 0 and x could have any value (positive, negative, or zero) and this would be respected
Not sufficient.
1+2)Still y could be 0, and in this case x, which now we know cannot be zero, could still equal a positive or negative number.
Example \(2*0\leq{0}\) this respects both conditions and x is positive, or \(-2*0\leq{0}\) here x is negative.
Not sufficient
E
Hi Zarrolou,
I thought mod of Zero was illegal.
in (ii) x could be zero. But together we know x cannot be zero hence negative.
\
|0|=0.
Is x negative?(1) x^2 is a positive number. This statement implies that \(x\neq{0}\). Not sufficient.
(2) x * |y| is not a positive number --> \(x * |y|\leq{0}\). If \(y=0\), then \(x\) could be ANY number. Not sufficient.
(1)+(2) Again, if \(y=0\), then \(x\) could be ANY number but 0 (excluded because of the first statement). Not sufficient.
Answer: E.