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venksune
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C.

I gives +1 or -1. Insufficient.
II depends on L. Insufficient.

Together x^2 = 1
So, II becomes LX+L = 12
= L(X+1) = 12
Here x cannot be -1 since that would lead to 0=12, so x = 1
Ans: Yes. C.
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hardworker_indian
C.

I gives +1 or -1. Insufficient.
II depends on L. Insufficient.

Together x^2 = 1
So, II becomes LX+L = 12
= L(X+1) = 12
Here x cannot be -1 since that would lead to 0=12, so x = 1
Ans: Yes. C.


I don't see how you got LX+L = 12 , given that x^2 =1 unless the question stem is LX + (x^2)L, but I don't see it that way. I see it as LX + x^2L , which means X is raised to the power 2L, which would make E the best choice
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venksune
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Pardon the ambiguity. Yes, I meant LX^2. My bad. really sorry, it is ambiguous. OA is C.

1.X^2=1 => X=+1 or -1. So, Insuff.
2. LX + LX^2 = 12 =>LX(1+X)=12 => X=-1, then LX(1+X) = 0. So, Insuff.

Combining both, if X=1, it will satisfy both conditions. So, C.



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