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Re: Is |x| + x < 2? (1) x > -1 (2) x < 0 [#permalink]
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Kudos
Rule of operating the mod ->

|x|
When assuming x>=0, |x| translates into x
When assuming x<0, |x| translates into -x
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Re: Is |x| + x < 2? (1) x > -1 (2) x < 0 [#permalink]
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