Is x y? (1) x^2 y (2) x – |y| 0

Question

Is x > y?

(1) x^2 > y

(2) x – |y| > 0

rohit8865 · Answer

(1) x^2 > y

Let x^2=4 and y=3
then( x=2)<(y=3)......NO
but x^2=16 and y=3
then( x=4)>(y=3)......YES.
Insuff.....

(2) x – |y| > 0
 x>IyI
it means x is a positive number
so x is always greater than Y wheather y is +ve or -ve
Suff...

Ans B

MathRevolution · Answer

Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Is x > y?

(1) x^2 > y
(2) x – |y| > 0

In the question above, in 2), x>|y| becomes -x<y<x, which is yes and sufficient.
Thus, B is the answer.

Vinayprajapati · Answer

Is x > y?

(1) x^2 > y
=> if y = 2 then for 
x=3, x^2>y but x>y
x=-3, x^2>y but x<y
Insufficient.
(2) x – |y| > 0 
x>lyl
lyl is always some positive value.
x is always positive with value greater then y.
Sufficient
B

Bunuel · Answer

Is x > y?

(1) x^2 > y:

If x = 1 and y = 0, then the answer will be YES.
If x = -1 and y = 0, then the answer will be NO.
Not sufficient.

(2) x – |y| > 0:

x > |y|. Now, if x is greater than the absolute value of y, then it must be greater than y itself. Sufficient.

Answer: B.

AkshdeepS · Answer

Question: Is x > y?

St 1: x^2 > y

Test some numbers: If x = 2 & y = 1,

then x^2 > y & also x > y

If x = -2 & y = 1,

then x^2 > y, but x < y

Insufficient

St 2: x – |y| > 0

means x > |y| (As we know absolute value is always >= 0)

If x > |y|, we can safely say that x > y

Sufficient.

(B)

Archit3110 · Answer

#1
x can b -ve or +ve insufficient
#2
x>lyl
y would be fraction value
IMO B

merajul · Answer

(1) x^2 > y .... can't able to prove anything (2) x - |y| > 0 => x-y > 0 => x>y => x+y > 0 => x > -y => -x

lakshya14 · Answer

In (2), can we take lYl on the other side and square it?

CEdward · Answer

Is x > y?

(1) x^2 > y
Clearly insufficient. 
x can be positive or negative and x^2 can be greater than y. 
x = -ve then y could be greater
x = +ve then y could be smaller

(2) x – |y| > 0
x > |y| 
RHS is always positive so we know that x will always be greater than y
Sufficient.

aritranandy8 · Answer

VeritasKarishma  plz explain

KarishmaB · Answer

(1) x^2 > y

Say x = 2 so x^2 = 4. 
We are given that 4 > y. Now note that y could be 3 or 1 (or infinite other values). So y may be greater than x or less than x. 
Not sufficient

(2) x – |y| > 0

x > |y|

Note that |y| is always positive. So |y| is either equal to y (when y is positive) or |y| is greater than y (when y is negative).
So |y| >= y
Since x is greater than |y|, it is certainly greater than y too (since y is equal to |y| or less than |y|).
Sufficient

Answer (B)

bumpbot · Answer

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Is x > y? (1) x^2 > y (2) x – |y| > 0

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