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Is x > y? (1) x^3 > 100y^7 (2) x > 0

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Is x > y? (1) x^3 > 100y^7 (2) x > 0  [#permalink]

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New post 16 Dec 2019, 00:26
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

58% (01:29) correct 42% (01:21) wrong based on 36 sessions

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Re: Is x > y? (1) x^3 > 100y^7 (2) x > 0  [#permalink]

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New post 16 Dec 2019, 01:55
Statement 1: \(x^3 > 100y^7\)
let's take the example: x= -3, y=-2 // \(x^3 > 100y^7\) // x < y
another example: x= 1000, y= 1 // \(x^3 > 100y^7\) // x > y
2 different solutions, Insufficient ............... A D / B C E

Statement 1: \(x > 0\) - Insufficient. Tells nothing about y ........... A D / B C E

Combining both statements.. x will always be greater than y ... 'C' is the winner but I am not sure about it :roll:
Bunuel wrote:
Is \(x > y\)?


(1) \(x^3 > 100y^7\)

(2) \(x > 0\)


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Is x > y? (1) x^3 > 100y^7 (2) x > 0  [#permalink]

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New post 16 Dec 2019, 13:13
Analyzing the question:
We have no information on x and y so we need to consider positive/negative values and fractional/whole number values.

Statement 1:
We can have x = 100 and y = 1 for x > y, or x = 1/100 and y = 1/99 for x < y. Insufficient.

Statement 2:
Insufficient.

Combined:
The key here is to see we cannot prove x > y with this information. As an example, the case x = 1/100 and y = 1/99 still gives x < y so combined information is still insufficient.

Ans: E


Bunuel wrote:
Is \(x > y\)?


(1) \(x^3 > 100y^7\)

(2) \(x > 0\)


Are You Up For the Challenge: 700 Level Questions

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Is x > y? (1) x^3 > 100y^7 (2) x > 0   [#permalink] 16 Dec 2019, 13:13
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