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Is |x| < |y|? (1) -x > y (2) y < 0 im usually

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VP
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Joined: 17 Jun 2008
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Is |x| < |y|? (1) -x > y (2) y < 0 im usually [#permalink]

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New post 03 Aug 2008, 05:48
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Is |x| < |y|?
(1) -x > y
(2) y < 0

im usually confused in absolute values ? kindly let me know the correct approach :shock:
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cheers
Its Now Or Never

Kudos [?]: 426 [0], given: 0

Manager
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Joined: 27 May 2008
Posts: 200

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Re: DS - absolute values [#permalink]

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New post 03 Aug 2008, 06:23
For absolute one should be very careful. Since the underlying value can be either negative or positive

for example if |x| >3 means it can go in both the sides
-3 < x < 3

So letz jump into the problem now

Statement 1 says: -x > y
so y should also be a negative with greater absolute value.
So SUFFICINET

Statement 2 says: y<0
So y is less than 0, but no idea abt the value of X. it can be either > or < or = y.

So answer shud be A.

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Manager
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Re: DS - absolute values [#permalink]

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New post 03 Aug 2008, 06:31
Sorry for the typo

for example if |x| <3 means it can go in both the sides
-3 < x < 3

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Director
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Re: DS - absolute values [#permalink]

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New post 03 Aug 2008, 06:50
spriya wrote:
Is |x| < |y|?
(1) -x > y
(2) y < 0

im usually confused in absolute values ? kindly let me know the correct approach :shock:


should be E

the Q is |x| < |y|
can be written as 4 conditions
x +ve, y +ve : x < y
x -ve, y +ve : -x < y
x -ve, y -ve : -x < -y
x +ve, y -ve : x < -y

statement 1 : only tells us about 4th condition, we know this condition only works when x is +ve and y is -ve ...so not suff
statement 2 : again not suff, doesn tell anything about x

combine : we 4th condition and y<0, but we also need x>0 to be sure ... not suff

Kudos [?]: 369 [0], given: 0

VP
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Joined: 17 Jun 2008
Posts: 1374

Kudos [?]: 426 [0], given: 0

Re: DS - absolute values [#permalink]

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New post 03 Aug 2008, 10:31
durgesh79 wrote:
spriya wrote:
Is |x| < |y|?
(1) -x > y
(2) y < 0

im usually confused in absolute values ? kindly let me know the correct approach :shock:


should be E

the Q is |x| < |y|
can be written as 4 conditions
x +ve, y +ve : x < y
x -ve, y +ve : -x < y
x -ve, y -ve : -x < -y
x +ve, y -ve : x < -y

statement 1 : only tells us about 4th condition, we know this condition only works when x is +ve and y is -ve ...so not suff
statement 2 : again not suff, doesn tell anything about x

combine : we 4th condition and y<0, but we also need x>0 to be sure ... not suff


Yes correct OA is E
Good explanation
we got to always consider sign while solving absolute values :(
i will take care
_________________

cheers
Its Now Or Never

Kudos [?]: 426 [0], given: 0

Re: DS - absolute values   [#permalink] 03 Aug 2008, 10:31
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Is |x| < |y|? (1) -x > y (2) y < 0 im usually

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