GMATD11
32) Is x<y?
a) z<y
b) z<x
Its is clear that alone a or b is not sufficient to answer the question
But can't we combine and perform subtraction OR we have to apply the rule that we don't know the sign of z so we can't cancel it.Pls let me know the exact reason.
You cannot subtract inequalities if they have the same sign. You can only add them in that case.
You can subtract them only if they have opposite signs though I always suggest to flip the sign of one of them and then add them.
Case 1:
a < b
c < d
Add: a + c < b + d (Correct)
Subtract: a - c < b - d (Incorrect)
Case 2:
a < b
c > d
Subtract: a - c < b - d (Correct)
Better yet, flip the sign and add:
a < b
d < c
Add: a + d < b + c (So that there is no confusion)
Note that either ways, you get the same resultant inequality
Another thing,
If you have a + b < a + c, you can cancel 'a' out irrespective of whether you know its sign or not. a is added/subtracted on both sides. Addition/subtraction of any number on both sides does not change the inequality.
Instead, if you have ab < ac, now you cannot cancel 'a' since you do not know its sign. a is multiplied/divided in this case. Multiplication/division by a negative number on both sides flips the sign of the inequality.