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Is x > y?
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Updated on: 04 Dec 2017, 00:00
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71% (00:54) correct 29% (00:52) wrong based on 141 sessions
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Is x > y? (1) x^2 > y (2) x – y > 0 OPEN DISCUSSION OF THIS QUESTION IS HERE: isxy1x2y2xy215485.html== Message from the GMAT Club Team == THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION. This discussion does not meet community quality standards. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you.
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Originally posted by siddhans on 19 Jun 2011, 03:51.
Last edited by Bunuel on 04 Dec 2017, 00:00, edited 3 times in total.
Edited the question.



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Re: Is x > y?
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19 Jun 2011, 06:13
siddhans wrote: Is x > y?
(1) x2 > y
(2) x – y > 0 st1: x^2>y x can be positive or negative ex: (5)^2 > 6 but 5 is not > 6................. in sufficient st 2: x> y when Y is postive x> y example X = 6 y = 5 6>5 when y is negative x>y 6>(5) 6>5 ( we cant assume Y to be 7 ...) hence B



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Re: Is x > y?
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19 Jun 2011, 12:59
sudhir18n wrote: siddhans wrote: Is x > y?
(1) x2 > y
(2) x – y > 0 st1: x^2>y x can be positive or negative ex: (5)^2 > 6 but 5 is not > 6................. in sufficient st 2: x> y when Y is postive x> y example X = 6 y = 5 6>5 when y is negative x>y 6>(5) 6>5 ( we cant assume Y to be 7 ...) hence B I did not get it... St 2 : when Y is positive x >y ex. x=6 and you are taking y =5???? Also, when y is ve why are you writing x > y??? how does mod work in this case? if its given x > y???



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Re: Is x > y?
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20 Jun 2011, 21:34
Can someone please reply? Also, how can we assume x is positive in statement 2?



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Re: Is x > y?
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20 Jun 2011, 21:40
y is always positive, but y may or may not be positive. If y < 0, then y = y. Also, x > y means x is > a positive number, so x is always positive. Read this : mathabsolutevaluemodulus86462.html
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Re: Is x > y?
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20 Jun 2011, 22:21
subhashghosh wrote: y is always positive, but y may or may not be positive. If y < 0, then y = y. Also, x > y means x is > a positive number, so x is always positive. Read this : mathabsolutevaluemodulus86462.htmlOk got it ...but in sudhir's ex st 2: x> y when Y is postive x> y example X = 6 y = 5 6>5 when y is negative x>y 6>(5) 6>5 ( we cant assume Y to be 7 ...) How come he says Y is +ve and takes y =5??? Is there some error?



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Re: Is x > y?
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20 Jun 2011, 22:23
siddhans wrote: subhashghosh wrote: y is always positive, but y may or may not be positive. If y < 0, then y = y. Also, x > y means x is > a positive number, so x is always positive. Read this : mathabsolutevaluemodulus86462.htmlOk got it ...but in sudhir's ex st 2: x> y when Y is postive x> y example X = 6 y = 5 6>5 when y is negative x>y 6>(5) 6>5 ( we cant assume Y to be 7 ...) How come he says Y is +ve and takes y =5??? Is there some error?Yes there is an error Y has to be 5 and not 5



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Re: Is x > y?
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Updated on: 13 Feb 2013, 08:50
Is x > y? (1) x^2 > y (2) x – y > 0 My understtanding: All statement 1 tells us for sure is x is not 0 Statement 2 we can break into two staments
x>y OR x>y
What I dont get is only one of those statements being true makes B the correct choice...so how is B the correct choice when there are two possibilities for a solution?
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Originally posted by manimgoindowndown on 13 Feb 2013, 08:42.
Last edited by Bunuel on 13 Feb 2013, 08:50, edited 1 time in total.
RENAMED THE TOPIC.



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Re: Is x > y?
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13 Feb 2013, 08:58
manimgoindowndown wrote: Is x > y? (1) x^2 > y (2) x – y > 0 My understtanding: All statement 1 tells us for sure is x is not 0 Statement 2 we can break into two staments
x>y OR x>y
What I dont get is only one of those statements being true makes B the correct choice...so how is B the correct choice when there are two possibilities for a solution? Yes u got it right way! but u gotta complete it buddy ya definitely S1 is not sufficent But S2 is a trap. x>y OR x>y assume numbers for x and y in this case let x=4 and y=3 so 4>3 like wise x=4 and y=3 this also 4>3 So x>y always will be x>y Hope i helped u
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Re: Is x > y?
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15 Feb 2013, 01:35
From F.S 1, we can have x=5,y=3. Thus , x^2>y, but x<y. Hence the answer is NO. Now, for x=5,y=3, x^2>y and x>y. Here the answer is a YES. Thus not sufficient. Fro F.S 2, xmod(y)>0. Thus, x>mod(y). Whatever be the sign of y, x>y(always). Sufficient. B.
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Re: Is x > y?
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15 Feb 2013, 02:16
manimgoindowndown wrote: Is x > y? (1) x^2 > y (2) x – y > 0 My understtanding: All statement 1 tells us for sure is x is not 0 Statement 2 we can break into two staments
x>y OR x>y
What I dont get is only one of those statements being true makes B the correct choice...so how is B the correct choice when there are two possibilities for a solution? From 2, we get that x  y is positive. Since y is postive, this means that x is also positive. So, if "y" is negative, it automatically means that x is greater than y. If "y" is positive, x  y still gives a postive number. Hence x is again greater than y. Answer is hence B.
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Re: Is x > y?
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03 Dec 2017, 23:59
siddhans wrote: Is x > y?
(1) x^2 > y
(2) x – y > 0 Is x > y?(1) x^2 > y: If x = 1 and y = 0, then the answer will be YES. If x = 1 and y = 0, then the answer will be NO. Not sufficient. (2) x – y > 0: x > y. Now, if x is greater than the absolute value of y, then it must be greater than y itself. Sufficient. Answer: B. OPEN DISCUSSION OF THIS QUESTION IS HERE: isxy1x2y2xy215485.html== Message from the GMAT Club Team == THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION. This discussion does not meet community quality standards. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you.
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Re: Is x > y? &nbs
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