Is -x/(-y)(-z) -ve?? 1) x*y 0 2)xyz0

Question

Is -x/(-y)(-z) -ve??

1) x*y >0
2)xyz>0

BG · Answer

Interesting.

A) Given X and Y are either both pos or neg but the sign of Z is unknown. Stmnt A is NOT suff
B) possible scenarios either X,Y,Z are pos or 2 of them are neg. In either case the stem is neg so B)

B) SUFF

Yurik79 · Answer

lets pick numbers x,y and z x=-1 y=-2 z =3 x-ve y-ve and z+ve Is -x/(-y)(-z) -ve?? 1/(2)*(-3) so it is -ve if x=1 y=-2 z=-3 -1/(2)*(3) it is -ve if x=-1 y=2 z=-3 1/-2*3 - ve Oops it seems like B it is :oops:

ps_dahiya · Answer

B

signs of xyz or x/yz or xy/z etc will always be same.

so for the sign purpose we can consider -x/(-y)(-z) as (-xyz)

B clearly says that xyz > 0 so
(-xyz) will always be less than 0, so will be -x/(-y)(-z)

FN · Answer

suppose y,z are both negative, -1, -1 and x is positive 1

-1/(- -1)*(- -1) the entire sum is negative..

IMO it should be C..

yezz · Answer

nice ralley everyone.

The OA is B

HOPE YOU ENJOYED IT

yezz · Answer

if we simplified 

-x/(-y*-z) to -x/yz = -1(x/yz)

and since x/yz will always be positive then -1(x/yz)
 will always be negative

that is the OE

Is -x/(-y)(-z) -ve?? 1) x*y >0 2)xyz>0

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