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Re: Is xy < 12? (1) x < 4 and y < 3 (2) x^2 < 121 and y^2 < 4
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06 Jul 2018, 07:30

Is xy < 12?

(1) x < 4 and y < 3.

If x = y = 0, then xy = 0 < 12. So, in this case we have an YES answer. If x = y = -10, then xy = 100 > 12. So, in this case we have a NO answer.

Not sufficient.

(2) x^2 < 121 and y^2 < 4:

-11 < x < 11 and -2 < y < 2.

If x = y = 0, then xy = 0 < 12. So, in this case we have an YES answer. If x = -10 and y = -1.5 then xy = 15 > 12. So, in this case we have a NO answer.

Not sufficient.

(1)+(2) -11 < x < 4 and -2 < y < 2:

If x = y = 0, then xy = 0 < 12. So, in this case we have an YES answer. If x = -10 and y = -1.5 then xy = 15 > 12. So, in this case we have a NO answer.

Not sufficient.

Answer: E.

Hope it's clear.

P.S. Please provide the OA's when posting questions. Thank you.
_________________

Re: Is xy < 12? (1) x < 4 and y < 3 (2) x^2 < 121 and y^2 < 4
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07 Jul 2018, 08:40

The key to getting this question right is to consider that x and y could be negative. While combining statements being careful with inequalities and testing appropriate cases as which give a "yes" and a "no" answer so that we can conclude "E" is the right answer.
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_________________ Manish

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Re: Is xy < 12? (1) x < 4 and y < 3 (2) x^2 < 121 and y^2 < 4 &nbs
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07 Jul 2018, 08:40