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gmatornot
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Is xy > x^2y^2? (1) 14x^2 = 3 (2) y^2 = 1 A. Statement 23 Aug 2006, 20:39
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Is xy > x^2y^2?

(1) 14x^2 = 3

(2) y^2 = 1

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT sufficient.



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gk3.14
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Is xy > x^2y^2? (1) 14x^2 = 3 (2) y^2 = 1 A. Statement 23 Aug 2006, 21:17
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E?
1. x = +/- 3/14^1/2; y is not known so INSUF
2. y =+/- 1; x is not known so INSUF

combined: if x positive and y is negative then it is less; if x positive and y positive more, so INSUF

Ans E?
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Is xy > x^2y^2? (1) 14x^2 = 3 (2) y^2 = 1 A. Statement 23 Aug 2006, 21:39
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gmatornot
Is xy > x^2y^2?

(1) 14x^2 = 3

(2) y^2 = 1
.
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x,y={ I , +, -, 0, ==, +-1/2, +-sqrt(2) }

(1) x^2 = 3/14
x = +- sqrt(3/14)
Take x= sqrt(3/14)
sub in Qstem
is y > y^2* sqrt(3/14)
is y(1- y*sqrt(3/14)) > 0
If y= 1 Yes
If y=0 No
BCE

(2) y = +- 1
If y =1 --> is x> x^2
If x=1 No
if x= 2 No
if x= -1 No
If x = 1/2 Yes
CE

(1)&(2)
Take
x= sqrt(3/14) & y =1
Qstem-->Is sqrt(3/14) > 3/14 Yes

Take x= - sqrt(3/14) & y=1
Qstem-->Is -sqrt(3/14) > 3/14 No

Hence E
I found this one tough

Heman
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Ruby
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Is xy > x^2y^2? (1) 14x^2 = 3 (2) y^2 = 1 A. Statement 23 Aug 2006, 21:52
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Answer is E.

TIP: When ever no number sign is given evaluate both +ve and -ve cases.
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prashrash
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Is xy > x^2y^2? (1) 14x^2 = 3 (2) y^2 = 1 A. Statement 24 Aug 2006, 08:44
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Yep. I got E too.

x^2*y^2 will always be +ve. But we don't know if xy will be +ve or -ve .. hence INSUFF.
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prashrash
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Is xy > x^2y^2? (1) 14x^2 = 3 (2) y^2 = 1 A. Statement 25 Aug 2006, 10:59
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heman

x,y={ I , +, -, 0, ==, +-1/2, +-sqrt(2) }
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pls explain what u mean by this stmt ?
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Is xy > x^2y^2? (1) 14x^2 = 3 (2) y^2 = 1 A. Statement 26 Aug 2006, 08:49
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prashrash
heman

x,y={ I , +, -, 0, ==, +-1/2, +-sqrt(2) }

pls explain what u mean by this stmt ?
Show more



Essentially I am reminding myself that x,y could be Integer, +ve Integer, -ve integer, zero, x could be == to y, fractions etc .

Since the Qstem does not specify any definite range of value for x,y it is important to try different ranges.

This was a technique I learnt from giddi's(Quant guru's) :P post

Heman
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prashrash
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Is xy > x^2y^2? (1) 14x^2 = 3 (2) y^2 = 1 A. Statement 26 Aug 2006, 14:05
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heman
prashrash
heman

x,y={ I , +, -, 0, ==, +-1/2, +-sqrt(2) }

pls explain what u mean by this stmt ?


Essentially I am reminding myself that x,y could be Integer, +ve Integer, -ve integer, zero, x could be == to y, fractions etc .

Since the Qstem does not specify any definite range of value for x,y it is important to try different ranges.

This was a technique I learnt from giddi's(Quant guru's) :P post

Heman
Show more


nice strategy! this way ensures that u check for all possible conditions. thanks for sharing it.



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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