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Updated on: 07 Feb 2021, 04:29
Originally posted by nitin1negi on 17 Jun 2014, 19:45.
Last edited by Bunuel on 07 Feb 2021, 04:29, edited 2 times in total.
Last edited by Bunuel on 07 Feb 2021, 04:29, edited 2 times in total.
Renamed the topic, edited the question, added the OA and moved to DS forum.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
53% (02:14) correct
47%
(02:06)
wrong
based on 171
sessions
History
Date
Time
Result
Not Attempted Yet
Is \(xy + xy < xy\) ?
(1) \(\frac{x^2}{y} < 0\)
(2) \(x^9*(y^3)^3 < (x^2)^4*y^8\)
(1) \(\frac{x^2}{y} < 0\)
(2) \(x^9*(y^3)^3 < (x^2)^4*y^8\)
20 Mar 2017, 16:48
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harshal123
Dear harshal123,
I'm happy to respond.
I will say that this Jamboree question looks remarkably like this MGMAT question. At least these are how the sources have been cited on GMAT Club. If these two companies really are the authors of these respective questions, I would say that something is suspicious here. I will let MGMAT and Jamboree sort that out.
Here are a couple blog articles you may find relevant:
Exponent Properties on the GMAT
Exponent Powers on the GMAT
First, let's decipher the prompt:
xy + xy < xy
subtract xy
xy < 0
That's what the question is really asking: is the product of those two variables negative?
Statement #1: \(\frac{x^2}{y} < 0\)
We know that neither variable can equal zero. Anything non-zero squared is positive, so x^2 is positive. Divide both sides by this.
\(\frac{1}{y} < 0\)
We know that y is negative. We know nothing about x. Thus, this statement, alone and by itself, is insufficient.
Statement #2: \(x^9(y^3)^3 < (x^2)^4 y^8\)
This can be simplified to
\((xy)^9 < (xy)^8\)
Again, we know that neither variable can be zero. Thus, xy is a non-zero product, and any non-zero number raised to an even power is positive. We know \((xy)^8\) is a positive number, so we can divide both sides of the inequality by this.
xy < 1
We know that the product is less than 1. It could be less than zero, but it doesn't have to be. Thus, this statement, alone and by itself, is insufficient.
Combined:
From S#1, we know y < 0
From S#2, we know xy < 1
Example #1: \(x = +2\), \(y = -3\). This satisfies both statements and gives a "yes" answer to the prompt.
Example #2: \(x = -2\), \(y = -\frac{1}{3}\). This satisfies both statements and gives a "no" answer to the prompt.
Two different answers, nothing is sufficient. Combined, the statements are not sufficient.
OA = (E)
Does all this make sense?
Mike
18 Jun 2014, 01:17
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nitin1negi
Is xy+xy<xy?
Is \(xy+xy<xy\)? --> cancel xy in both sides: is \(xy<0\)? So, the question basically asks whether x and y have the opposite signs.
(1) x^2/y<0. This statement implies that y is negative and x can be anything but zero. Not sufficient.
(2) x^9*(y^3)^3 < (x^2)^4*y^8 --> \((xy)^9<(xy)^8\). Since \((xy)^8>0\) (from the inequality we can deduce that neither of the unknowns is zero, thus even power of xy will ensure that it's positive), then we can safely reduce by it: \(xy<1\) (\(xy\neq{0}\)). So, we cannot say whether \(xy<0\). Not sufficient.
(1)+(2) \(y<0\) and \(xy<1\). If \(x=-\frac{1}{2}\) and \(y=-1\), then the answer is NO but if \(x=1\) and \(y=-1\), then the answer is YES. Not sufficient.
Answer: E.
Hope it's clear.
P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html pay attention to rules, 2, 3, 5 and 7. Thank you.
