sj296Well for DS question the objective while solving should be try and make statement stand invalid/insufficient for target..
Which has been done for both cases in my solution..
I could make the #2 stand invalid by the reasoning I mentioned so I did not pick y as -ve also x is given in mod so it's better to test cases Of non zero inside mod..
Your reasoning for #1 is right as well, fraction values can also be taken to make statement invalid but then testing it would be a task for target .. so go for whats quick and gets you correct answer.
sj296 wrote:
Archit3110 wrote:
is xy>y^2
y*(x-y)>0
is y>0 and x>y
#1
yx < 1
possible when either of x or y is -ve
insufficient
#2
lxl>y
y is always +ve or 0 , but x can be +ve or -ve
we get yes & no to target insufficient
from 1 &2
y is +ve or y = 0 and x is -ve
in that case y*( x-y) can be >0 or =0
insufficient
option E is correct
Bunuel wrote:
Is xy > y^2 ?
(1) yx < 1
(2) |x| > y
Hey
Archit3110In statement 1, it need not be -ve, right?
If x & y are fractions then also xy will satisfy the condition. It's not given that x & y are integers.
Moreover, in statement 2 y can be -ve when x = 0. Why did you write that y is always +ve or 0? Just wanted to confirm the reasoning here.
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