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Asked: Is xyz > 0 ?

(1) (x - 3)(y - 3) > 0
Since z is unknown
NOT SUFFICIENT

(2) z > 0
Since x & y are unknown
NOT SUFFICIENT

(1) + (2)
(1) (x - 3)(y - 3) > 0
(2) z > 0
Since z>0; xyz>0 if xy > 0
(x - 3)(y - 3) > 0
Case 1: Either both x-3>0 and y-3>0
x>3>0 & y>3>0; xyz>0
Case 2: Both x-3<0 and y-3<0
x<3 and y<3
If x= -2; y = 2; xy<0
But if x=2; y=2; xy>0
NOT SUFFICIENT

IMO E
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