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14 Feb 2016, 05:32
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
54% (00:41) correct
46%
(00:38)
wrong
based on 226
sessions
History
Date
Time
Result
Not Attempted Yet
14 Feb 2016, 11:46
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(1) (y - 3)(x - 4) = 0
either y-3 = 0 or x-4 =0
=> either y=3 or x=4
Not sufficient
(2) (x - 4) = 0
=> x=4
Not sufficient as we have no information about value of y
Answer E
either y-3 = 0 or x-4 =0
=> either y=3 or x=4
Not sufficient
(2) (x - 4) = 0
=> x=4
Not sufficient as we have no information about value of y
Answer E
15 Feb 2016, 00:03
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
Is y = 3?
(1) (y - 3)(x - 4) = 0
(2) (x - 4) = 0
In the original condition, there is 1 variable(x). But, on the whole, there are 2 variables(x,y), which should match with the number of equations. So you need 1 equation. For 1) 1 equation, for 2) 1 equation, which is likely to make C the answer. When 1) & 2), if x=4, y=3 -> yes and y=4 -> no, which is not sufficient. Therefore, the answer is E.
For cases where we need 2 more equations, such as original conditions with “2 variables”, or “3 variables and 1 equation”, or “4 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 70% chance that C is the answer, while E has 25% chance. These two are the majority. In case of common mistake type 3,4, the answer may be from A, B or D but there is only 5% chance. Since C is most likely to be the answer using 1) and 2) separately according to DS definition (It saves us time). Obviously there may be cases where the answer is A, B, D or E.
Is y = 3?
(1) (y - 3)(x - 4) = 0
(2) (x - 4) = 0
In the original condition, there is 1 variable(x). But, on the whole, there are 2 variables(x,y), which should match with the number of equations. So you need 1 equation. For 1) 1 equation, for 2) 1 equation, which is likely to make C the answer. When 1) & 2), if x=4, y=3 -> yes and y=4 -> no, which is not sufficient. Therefore, the answer is E.
For cases where we need 2 more equations, such as original conditions with “2 variables”, or “3 variables and 1 equation”, or “4 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 70% chance that C is the answer, while E has 25% chance. These two are the majority. In case of common mistake type 3,4, the answer may be from A, B or D but there is only 5% chance. Since C is most likely to be the answer using 1) and 2) separately according to DS definition (It saves us time). Obviously there may be cases where the answer is A, B, D or E.
