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# Is y between 1 and 2, exclusive?

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Math Expert
Joined: 02 Sep 2009
Posts: 56244
Is y between 1 and 2, exclusive?  [#permalink]

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29 Aug 2016, 04:01
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45% (medium)

Question Stats:

67% (01:46) correct 33% (01:50) wrong based on 48 sessions

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Is y between 1 and 2, exclusive?

(1) y^2 is less than y
(2) y^2 + y is between 1 and 2, exclusive

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Manager
Joined: 15 Feb 2016
Posts: 60
GMAT 1: 710 Q48 V40
Is y between 1 and 2, exclusive?  [#permalink]

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29 Aug 2016, 14:17
Bunuel wrote:
Is y between 1 and 2, exclusive?

(1) y^2 is less than y
(2) y^2 + y is between 1 and 2, exclusive

From statement 1 :

The only time the square of a number is smaller than the number is when the number is a fraction between 0 and 1 (when denominator is greater than numerator)

Since Y^2 is less than y , y must fall between 0 and 1 so clearly not between 1 and 2. Sufficient

From statement 2:

y(y+1) is between 1 and 2 , exclusive

Let's take y=1

If y=1, y(y+1) = 2

so y is less than 1 hence not between 1 and 2. Sufficient

Hope this is correct I suck at inequalities
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Manager
Joined: 28 Jun 2016
Posts: 216
Concentration: Operations, Entrepreneurship
Re: Is y between 1 and 2, exclusive?  [#permalink]

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29 Aug 2016, 15:33
St 1: if y^2 < y, then y has to be a positive proper fraction. So 0<y<1.

Sufficient

St 2: if 1<y<2 , then 2< y^2+y <6;
But as per statement, 1 < y^2+y < 2.
Therefore, y is not within the range of 1 and 2.

Sufficient.

D

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Manager
Joined: 17 Nov 2014
Posts: 51
Location: India
Re: Is y between 1 and 2, exclusive?  [#permalink]

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30 Aug 2016, 09:18
Statement 1:

The only time the square of a number is smaller than the number is when the number is a fraction between 0 and 1, i.e 0<Y<1

so clearly Y doesn't fall between 1 and 2. Sufficient

Statement 2:

Any number greater than 1 when squared upon and added to itself will result in a value greater than 2. Hence Y cant between 1 and 2.

If $$Y$$=1,$$Y^2$$= 1 ; $$Y$$+$$Y^2$$ = 2, hence its not in the range (1<Y<2),

If $$Y$$=1.5 , $$Y^2$$= 1.25 ; $$Y$$+$$Y^2$$= 2.25, hence its not in the range (1<Y<2).

SO, Sufficient

Director
Joined: 27 May 2012
Posts: 814
Is y between 1 and 2, exclusive?  [#permalink]

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18 Jul 2018, 04:10
Bunuel wrote:
Is y between 1 and 2, exclusive?

(1) y^2 is less than y
(2) y^2 + y is between 1 and 2, exclusive

Dear Moderator,

Although I got this correct , still I may be missing something .

for statement 1: 0 <y <1

for statement 2 if Y = 1/2 then y^2 + y is between 1 and 2, exclusive is not satisfied

for statement 2, y seems to be : -2 < y <-1

Arn't the two statements contradicting each other?
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Is y between 1 and 2, exclusive?   [#permalink] 18 Jul 2018, 04:10
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