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Curious to know whether z or b can be negative. In general, do we have to consider the case for negative remainders as well in such questions
Please shed some light on this.
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jogeshanand
Curious to know whether z and b can be negative. In general, do we have to consider the case for negative remainders as well in such questions
Please shed some light on this.

No, at least on the GMAT.

OG12:
If \(x\) and \(y\) are positive integers, there exist unique integers \(q\) and \(r\), called the quotient and remainder, respectively, such that \(y =divisor*quotient+remainder= xq + r\) and \(0\leq{r}<x\).

Theory on remainders problems: remainders-144665.html
Tips: tips-and-hints-for-specific-quant-topics-with-examples-172096.html#p1376126

Units digits, exponents, remainders problems: new-units-digits-exponents-remainders-problems-168569.html

All DS remainders problems to practice: search.php?search_id=tag&tag_id=198
All PS remainders problems to practice: search.php?search_id=tag&tag_id=199

Hope this helps.
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selim
When the positive integer x is divided by the positive integer y the quotient is 2 and the remainder is z. when x is divided by the positive integer a the quotient is 3 and the remainder is b. Is z>b ?

1)the ration of y to a is less than 3 to 2.
2)the ratio of y to a is greater than 2 to 3.

When the positive integer x is divided by the positive integer y the quotient is 2 and the remainder is z

i.e. x = 2y + z


when x is divided by the positive integer a the quotient is 3 and the remainder is b

i.e. x = 3a + b


i.e. 2y + z = 3a + b

Question : Is z > b ?
Or
Question : Is 2y > 3a ?

Statement 1: the ratio of y to a is less than 3 to 2.

i.e. y / a < 3/2
i.e. 2y < 3a
SUFFICIENT

Statement 2: the ratio of y to a is greater than 2 to 3

i.e. y / a > 2/3
i.e. 3y < 2a
NOT SUFFICIENT

Answer: Option A
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As per question

X=2y+z
X=3a+b

2y+z=3a+b

I)y/a<1.5
3a>2y so in order to maintain equality
Z>b sufficient

II)y/a>0.6
3a can be > or < 2y
So can't say about z or b

A is answer

Posted from my mobile device
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Bunuel
i approached second statement as if y/a is greater than 2/3 which is equivalent to 0.66 , so i chose 3/4 which is greater than 2/3 as the statement states then putting the value in equation i finally got z=6+b which shows that z is greater than b. kindly,tell me what is wrong in this approach?
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Madhavsinghyadav
Bunuel

When the positive integer x is divided by the positive integer y, the quotient is 2 and the remainder is z. When x is divided by the positive integer a, the quotient is 3 and the remainder is b. Is z > b?

(1) The ratio of y to a is less than 3 to 2.
(2) The ratio of y to a is greater than 2 to 3.

i approached second statement as if y/a is greater than 2/3 which is equivalent to 0.66 , so i chose 3/4 which is greater than 2/3 as the statement states then putting the value in equation i finally got z=6+b which shows that z is greater than b. kindly,tell me what is wrong in this approach?
­­
Why should y/a > 2/3 mean that y/a is necessarily 3/4? Please review solution HERE. It's quite clear.
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