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metallicafan
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Concentration: Finance, SMEs, Developing countries, Public sector and non profit organizations
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14 Dec 2011, 09:57
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
84% (01:18) correct
16%
(01:46)
wrong
based on 82
sessions
History
Date
Time
Result
Not Attempted Yet
14 Dec 2011, 10:24
Kudos
Bookmarks
Should be E.
We dont have any information about x,y or z to start with.
1) xz>yz
=> z <> 0 (since if it is = 0 this inequality doesnt hold good), we also get x > y => insufficient
2) xy>yz
=> y<> 0 (since if it is = 0 this inequality doesnt hold good), we also get x>z => insufficient
Combining both we get tget relationship x>y and x>z
we cannot get any further information.
Hence E
We dont have any information about x,y or z to start with.
1) xz>yz
=> z <> 0 (since if it is = 0 this inequality doesnt hold good), we also get x > y => insufficient
2) xy>yz
=> y<> 0 (since if it is = 0 this inequality doesnt hold good), we also get x>z => insufficient
Combining both we get tget relationship x>y and x>z
we cannot get any further information.
Hence E
14 Dec 2011, 16:30
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iamgame
The conclusions you've drawn above (highlighted in red) are not quite right. If you know from Statement 1 that
xz > yz
we cannot just divide by z on both sides to get x > y. We don't know if z is positive or negative (that's the question after all!). If z is positive, we could divide by z to find that x > y, but if z is negative, when we divide by z on both sides we need to reverse the inequality; we would find that x < y.
As for the question,
Is z < 0?
(1) xz > yz
(2) xy > yz
it is easy to come up with a scenario where all three letters are positive since x is on the left side of each inequality - we just need to make x large. So if x = 100, y = 1 and z = 1, then the statements will be true and z > 0. We can also come up with a scenario where z < 0. If, say, z = -1, then for Statement 1 to be true, x will need to be smaller than y. If we make x and y positive and z negative, Statement 2 will be true (the left side will be positive and the right side will be negative), so we could have x = 1, y = 2 and z = -1. So the answer is E.
