Jack had to complete an assignment within the given deadline.....

Couldn't " 8500 more words during the last 7 days" be intended as 8500 words in addition to the prefixed plan of 1000?

Let's take A as number of days for which he wrote 700 words.
Total words=700*A
His target is to write 1000 words per day. Lets assume he followed this for x days.So total words he would have completed will be 1000*x.
Now we know for last 7 days he has words remaining =8500

First equation will be:-
700*A+8500=1000*x -->(1)------------No of words.

Second equation
A+7=x-->(2)

(A is the number of days where he wrote 700 words per day, 7 is the number where he wrote a total of 8500 words and x is the total number of days).

We need to find out A,which will come out as 5.

IMO C.

If we were to take the total # of days Jack planned to write as 'x', then the total number of words he was going to write would be 1000x.

Now, he wrote 700 words per day, for certain # of days and then realized he would need to write 8500 words in the last 7 days.

Algebraically, this can be represented as.

700 * (x-7) + 8500 = 1000 * x

700x - 4900 + 8500 = 1000x

300x = 3600

x = 12

Hence, the total # of days Jack planned to write was 12, and the number of days he wrote 700 words was (12 - 7) = 5. Answer would be 'C'.

Solution

Given:

• Jack decided to write 1000 words per day
• But, he could write only 700 words per day, for initial some days
• In the last 7 days, he was left with 8500 words to finish

To find:

• The number of days, where he wrote only 700 words per day

Approach and Working:

• Let us assume that the number of days, where he wrote only 700 words per day = x

o Number of words missed on each day, during this period = 1000 – 700 = 300
o Thus, the number of words missed on x days = 300 * x

• So, according to his original plan, in the last 7 days, he must write 7 * 1000 = 7000 words.

o But, he had to write 8500 words, which implies, in the first few days, he couldn’t write a total of 8500 – 7000 = 1500 words

• Therefore, 300x =1500

o Implies, x = 5

Hence, the correct answer is Option C.

Answer: C

Let, Total \(N \) Days will require

Total words \(1000N\)

\(∴ \ 1000N=700(N-7)+8500\)

\(⇒1000N=700N-4900+8500\)

\(⇒ 300N=3600\)

\(⇒ N=12\)

He wrote only 700 words in 12-7=5 days

The answer is \(C\)

[quote="EgmatQuantExpert"]Jack had to complete an assignment within the given deadline. So, he decided to write 1000 words per day. But, he could write only 700 words per day at first, then he realized that he needs to write 8500 more words during the last 7 days before the deadline. What is the number of days, where he wrote only 700 words per day?

A. 3
B. 4
C. 5
D. 7
E. 12

Jack initially assumed that he’ll complete the work in ‘n’ days if he covers 1000 words per day.

But, he writes 700 words per day for some days and continues with writing 8500 words for remaining 7 days.

N days is the days after which the work will get completed. 700 words will be written for the remaining days of the total deadline. So, 700 words written for n-7 days

To find: n-7


1000 x n = 700 x (n-7) + 8500 —-> I’m equating the total no. Of words written in this period

1000n = 700n - 4900 + 8500

300 n = 3600
N=12

N-7 = 5