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FightToSurvive
Joined: 18 Sep 2014
Last visit: 15 Dec 2016
Posts: 198
Given Kudos: 5
Schools: ISB '18 (A) Fisher '19 (II) Smeal Penn State "19 (A$) Kelley '19 (S) Olin '19 (S) Simon '19 (A$) Broad '19 (S)
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20 Nov 2015, 11:52
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B because the first term - the units digit is 6 and any power will result as 6 as units digit.
Second term is important as because 4 to the power even term gives 6 as units digit and for odd its 4.
Second term is important as because 4 to the power even term gives 6 as units digit and for odd its 4.
20 Nov 2015, 21:41
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If N = ( 1436)^A*(1054)^B. Where A and B are positive integers. What is the units digit of N?
(1) A + B = 6
(2) B = 2
Answer- B
This seems easy.
For units digit, U need to know about the units place digit of the numbers multiplied.
From given equation 1436^6- Units digit will always be 6.
6^1=6 odd power
6^2=36 even power
6^3=216 odd power
6^4=1296 even power....... continues
For 1054^B- we need to know the units place only so main focus will be on that only.
4^1=4 odd power
4^2=16 even power
4^3=64 odd power
4^4=256 even power.......continues
Statement-1 A+B=6. It could be 5+1 or 2+4 so 6*4 or 6*6 units place values are different, we are getting 2 values, so statement is not sufficient.
Statement-2 B=2 For A units digit value is fixed but in this case, B's units digit value is fixed too (which was required). Hence we get answer as 6*6= 6 as units digit-
Hence Sufficient
(1) A + B = 6
(2) B = 2
Answer- B
This seems easy.
For units digit, U need to know about the units place digit of the numbers multiplied.
From given equation 1436^6- Units digit will always be 6.
6^1=6 odd power
6^2=36 even power
6^3=216 odd power
6^4=1296 even power....... continues
For 1054^B- we need to know the units place only so main focus will be on that only.
4^1=4 odd power
4^2=16 even power
4^3=64 odd power
4^4=256 even power.......continues
Statement-1 A+B=6. It could be 5+1 or 2+4 so 6*4 or 6*6 units place values are different, we are getting 2 values, so statement is not sufficient.
Statement-2 B=2 For A units digit value is fixed but in this case, B's units digit value is fixed too (which was required). Hence we get answer as 6*6= 6 as units digit-
Hence Sufficient
21 Nov 2015, 09:53
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
If N = ( 1436)^A*(1054)^B. Where A and B are positive integers. What is the units digit of N?
(1) A + B = 6
(2) B = 2
If we modify the original condition, n=( 1436)^A*(1054)^B=(...6)(1054)^B. (Numbers with the units digit of 6 results in the units digit of 6 no matter what we multiply). We only need to know B so the answer becomes (B).
Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
If N = ( 1436)^A*(1054)^B. Where A and B are positive integers. What is the units digit of N?
(1) A + B = 6
(2) B = 2
If we modify the original condition, n=( 1436)^A*(1054)^B=(...6)(1054)^B. (Numbers with the units digit of 6 results in the units digit of 6 no matter what we multiply). We only need to know B so the answer becomes (B).
Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
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