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Bunuel
James and Logan are taking batting practice. If their individual probabilities of hitting a homerun are x and y, respectively, then what is the probability that James will not hit a homerun but Logan will?

A. x – xy
B. x – y^2
C. y – xy
D. y/x
E. 1/x - y

If P(James hits home run) = x, then P(James does NOT hit home run) = 1-x
Given: P(Logan hits home run) = y

So, P(James will not hit a home run AND Logan hits a home run) = P(James will not hit a home run) X P(Logan hits a home run)
= (1-x) X (y)
= y - yx

Answer: C

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Bunuel
James and Logan are taking batting practice. If their individual probabilities of hitting a homerun are x and y, respectively, then what is the probability that James will not hit a homerun but Logan will?

A. x – xy
B. x – y^2
C. y – xy
D. y/x
E. 1/x - y

Given: James and Logan are taking batting practice. If their individual probabilities of hitting a homerun are x and y, respectively.

Asked: What is the probability that James will not hit a homerun but Logan will?

Probability that James will not hit a homerun but Logan will = (1-x)y = y-xy

IMO C
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Bunuel
James and Logan are taking batting practice. If their individual probabilities of hitting a homerun are x and y, respectively, then what is the probability that James will not hit a homerun but Logan will?

A. x – xy
B. x – y^2
C. y – xy
D. y/x
E. 1/x - y

The probability that James will not hit a homerun but Logan will is (1 - x)(y) = y - yx.

Answer: C
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