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# Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour

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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5255
GMAT 1: 800 Q59 V59
GPA: 3.82
Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink]

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11 May 2016, 20:13
00:00

Difficulty:

5% (low)

Question Stats:

83% (00:38) correct 17% (00:54) wrong based on 127 sessions

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Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour and the rest 20 miles at 30 miles per hour, what is the average speed of the entire trip?
A. 30miles/1hr
B. 36miels/1hr
C. 40miles/1hr
D. 42miels/1hr
E. 45miles/1hr

* A solution will be posted in two days.
[Reveal] Spoiler: OA

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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
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"Only $79 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Expert Joined: 02 Aug 2009 Posts: 5774 Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink] ### Show Tags 12 May 2016, 09:03 Expert's post 1 This post was BOOKMARKED MathRevolution wrote: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour and the rest 20 miles at 30 miles per hour, what is the average speed of the entire trip? A. 30miles/1hr B. 36miels/1hr C. 40miles/1hr D. 42miels/1hr E. 45miles/1hr * A solution will be posted in two days. Since the distance travelled is same... avg speed =$$\frac{2ab}{(a+b)}= \frac{2*60*30}{(30+60)} = 40$$ C _________________ Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372 Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html GMAT online Tutor Current Student Joined: 18 Oct 2014 Posts: 886 Location: United States GMAT 1: 660 Q49 V31 GPA: 3.98 Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink] ### Show Tags 12 May 2016, 09:42 Since the distance traveled is same, we can apply direct formula= 2XS1XS2/S1+S2 2X60X30/90= 40 'C' is the answer _________________ I welcome critical analysis of my post!! That will help me reach 700+ Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5255 GMAT 1: 800 Q59 V59 GPA: 3.82 Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink] ### Show Tags 14 May 2016, 02:49 Average speed = the total distance / the total time. The first 20 miles took 1/3 hr and the rest 20 miles took 2/3 hr. Then, the average speed=(20 miles + 20 miles)/(1/3 + 2/3) hr= 40 miles/1hr. Hence, the correct answer is C. _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 3 month Online Course"
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Intern
Joined: 25 Jun 2015
Posts: 9
Location: Portugal
GMAT 1: 370 Q37 V37
GPA: 2.92
Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink]

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05 Aug 2016, 05:21
I did like this: 20/60 + 20/30 = 6/6 = 1
Intern
Joined: 06 Dec 2017
Posts: 1
Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink]

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15 Dec 2017, 02:00
Found this to be the most simpler method
20miles/60+20miles/30=40miles/x
or, 20/60+40/60= 40/x
or, 1=40/x
or, x=40
Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour   [#permalink] 15 Dec 2017, 02:00
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