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Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour

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Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink]

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New post 11 May 2016, 20:13
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Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour and the rest 20 miles at 30 miles per hour, what is the average speed of the entire trip?
A. 30miles/1hr
B. 36miels/1hr
C. 40miles/1hr
D. 42miels/1hr
E. 45miles/1hr


* A solution will be posted in two days.
[Reveal] Spoiler: OA

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Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink]

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New post 12 May 2016, 09:03
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MathRevolution wrote:
Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour and the rest 20 miles at 30 miles per hour, what is the average speed of the entire trip?
A. 30miles/1hr
B. 36miels/1hr
C. 40miles/1hr
D. 42miels/1hr
E. 45miles/1hr


* A solution will be posted in two days.


Since the distance travelled is same...
avg speed =\(\frac{2ab}{(a+b)}= \frac{2*60*30}{(30+60)} = 40\)
C
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Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink]

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New post 12 May 2016, 09:42
Since the distance traveled is same, we can apply direct formula= 2XS1XS2/S1+S2

2X60X30/90= 40 'C' is the answer
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Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink]

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New post 14 May 2016, 02:49
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Average speed = the total distance / the total time. The first 20 miles took 1/3 hr and the rest 20 miles took 2/3 hr. Then, the average speed=(20 miles + 20 miles)/(1/3 + 2/3) hr= 40 miles/1hr. Hence, the correct answer is C.
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Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink]

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New post 05 Aug 2016, 05:21
I did like this: 20/60 + 20/30 = 6/6 = 1
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Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink]

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New post 15 Dec 2017, 02:00
Found this to be the most simpler method
20miles/60+20miles/30=40miles/x
or, 20/60+40/60= 40/x
or, 1=40/x
or, x=40
Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour   [#permalink] 15 Dec 2017, 02:00
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