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• ### $450 Tuition Credit & Official CAT Packs FREE November 15, 2018 November 15, 2018 10:00 PM MST 11:00 PM MST EMPOWERgmat is giving away the complete Official GMAT Exam Pack collection worth$100 with the 3 Month Pack ($299) # Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics Author Message TAGS: ### Hide Tags Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 6499 GMAT 1: 760 Q51 V42 GPA: 3.82 Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour [#permalink] ### Show Tags 11 May 2016, 19:13 00:00 Difficulty: 5% (low) Question Stats: 84% (01:06) correct 16% (01:38) wrong based on 139 sessions ### HideShow timer Statistics Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour and the rest 20 miles at 30 miles per hour, what is the average speed of the entire trip? A. 30miles/1hr B. 36miels/1hr C. 40miles/1hr D. 42miels/1hr E. 45miles/1hr * A solution will be posted in two days. _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour  [#permalink]

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12 May 2016, 08:03
MathRevolution wrote:
Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour and the rest 20 miles at 30 miles per hour, what is the average speed of the entire trip?
A. 30miles/1hr
B. 36miels/1hr
C. 40miles/1hr
D. 42miels/1hr
E. 45miles/1hr

* A solution will be posted in two days.

Since the distance travelled is same...
avg speed =$$\frac{2ab}{(a+b)}= \frac{2*60*30}{(30+60)} = 40$$
C
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Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour  [#permalink]

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12 May 2016, 08:42
Since the distance traveled is same, we can apply direct formula= 2XS1XS2/S1+S2

2X60X30/90= 40 'C' is the answer
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Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour  [#permalink]

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14 May 2016, 01:49
Average speed = the total distance / the total time. The first 20 miles took 1/3 hr and the rest 20 miles took 2/3 hr. Then, the average speed=(20 miles + 20 miles)/(1/3 + 2/3) hr= 40 miles/1hr. Hence, the correct answer is C.
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Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour  [#permalink]

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05 Aug 2016, 04:21
I did like this: 20/60 + 20/30 = 6/6 = 1
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Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour  [#permalink]

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15 Dec 2017, 01:00
Found this to be the most simpler method
20miles/60+20miles/30=40miles/x
or, 20/60+40/60= 40/x
or, 1=40/x
or, x=40
Re: Jane goes the trip of 40miles, the first 20 miles at 60 miles per hour &nbs [#permalink] 15 Dec 2017, 01:00
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