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# Jane is in a certain ticket line in which each of the other

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Director
Joined: 20 Sep 2006
Posts: 640
Jane is in a certain ticket line in which each of the other [#permalink]

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27 Aug 2008, 14:05
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Jane is in a certain ticket line in which each of the other people in the line is either behind her or ahead of her. In the line, the number of people ahead of Jane is 5 more than the number of people behind her. What is the total number of people in the line?

(1) There are 11 people ahead of Jane in the line.
(2) The total number of people in the line is 3 times the number of people behind Jane.
Manager
Joined: 10 Sep 2007
Posts: 150
Re: DS ticket line [#permalink]

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27 Aug 2008, 14:21
y y +5

1. y+5=11 y=6, 6+6+5+1(jane)= 18 people ahead

2. 3y=2y+6 y=6, 6+6+5+1(jane)= 18 people ahead

I will go with "D"
SVP
Joined: 29 Aug 2007
Posts: 2453
Re: DS ticket line [#permalink]

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27 Aug 2008, 14:33
rao_1857 wrote:
Jane is in a certain ticket line in which each of the other people in the line is either behind her or ahead of her. In the line, the number of people ahead of Jane is 5 more than the number of people behind her. What is the total number of people in the line?

(1) There are 11 people ahead of Jane in the line.
(2) The total number of people in the line is 3 times the number of people behind Jane.

from 1:
11 = 5 + x
x = 6
total = 18

from 2:
t = x+x+5+1 = 2x +6
t = 3x
3x = 2x + 6
x = 6
t = 18

D.
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Director
Joined: 20 Sep 2006
Posts: 640
Re: DS ticket line [#permalink]

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27 Aug 2008, 16:12
Thanks guys .. I again did the stupid mistake ... forgot to count Jane while counting the total number of person.
SVP
Joined: 29 Aug 2007
Posts: 2453
Re: DS ticket line [#permalink]

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27 Aug 2008, 18:01
rao_1857 wrote:
Thanks guys .. I again did the stupid mistake ... forgot to count Jane while counting the total number of person.

so you are Jane :l ol:
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Re: DS ticket line   [#permalink] 27 Aug 2008, 18:01
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# Jane is in a certain ticket line in which each of the other

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