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# Janel was shopping for pencils and pens at a Fung's Stationary Store

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Math Expert
Joined: 02 Sep 2009
Posts: 41886

Kudos [?]: 128688 [0], given: 12182

Janel was shopping for pencils and pens at a Fung's Stationary Store [#permalink]

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17 Sep 2017, 03:02
00:00

Difficulty:

35% (medium)

Question Stats:

56% (00:51) correct 44% (00:30) wrong based on 33 sessions

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Janel was shopping for pencils and pens at a Fung's Stationary Store where pencils costs \$2 each and pens costs \$3 each, how many pens did she buy?

(1) Janel spent \$5 total.
(2) Janel bought a total of 2 pencils and pens.
[Reveal] Spoiler: OA

_________________

Kudos [?]: 128688 [0], given: 12182

Intern
Joined: 29 Aug 2017
Posts: 23

Kudos [?]: 1 [0], given: 28

Janel was shopping for pencils and pens at a Fung's Stationary Store [#permalink]

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17 Sep 2017, 05:23
Bunuel wrote:
Janel was shopping for pencils and pens at a Fung's Stationary Store where pencils costs \$2 each and pens costs \$3 each, how many pens did she buy?

(1) Janel spent \$5 total.
(2) Janel bought a total of 2 pencils and pens.

Let x be the number of pencils bought and y be the number of pens bought.
y = ?

Statement 1:
5 = total amount spent
Amount spent by Janel = 2*x + 3*y (since each of the x pencils costs 2 dollars and each of the y pens costs 3 dollars)
5 = 2*x + 3*y
Since x and y are the number of pencils and pens bought respectively, they are non-negative integers. The only set of integers satisfying the given condition is 1, 1. (if x = 0, y = 5/3 which is not an integer; if y = 0, x = 5/2 which is not an integer; if x = 1; y = (5-2)/3 = 1; if x = 2, y = 1/3 which is not an integer; if y = 2, x = -1/2 which is neither positive nor an integer. Thus, no other non-negative integer values satisfy the condition except for 1,1)
Therefore, x = 1, y = 1
Statement 1 is sufficient.

Statement 2:
2 = total of pens and pencils
2 = x + y
This implies, x can 0 and y can be 2, x can be 1 and y can be 1 and x can be 2 and y can be 0 (since only non-negative integers are allowed)
Therefore, this statement does not yield a unique value for y.
So, statement 2 is not sufficient.

Hence, since only statement 1 is sufficient, answer is A.

Kudos [?]: 1 [0], given: 28

Intern
Joined: 25 Mar 2016
Posts: 33

Kudos [?]: 5 [0], given: 2

Location: India
Concentration: Finance, General Management
WE: Other (Other)
Re: Janel was shopping for pencils and pens at a Fung's Stationary Store [#permalink]

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18 Sep 2017, 10:41
From statement 1 we can deduce that in \$5 janel can buy At most 1 pen

From statement 2 we can deduce that janel bought 1 pen and 1 pencil

So from both the statement we can get answer So the answer will be D

Kudos [?]: 5 [0], given: 2

Manager
Status: love the club...
Joined: 24 Mar 2015
Posts: 168

Kudos [?]: 13 [0], given: 400

Janel was shopping for pencils and pens at a Fung's Stationary Store [#permalink]

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23 Sep 2017, 23:45
Bunuel wrote:
Janel was shopping for pencils and pens at a Fung's Stationary Store where pencils costs \$2 each and pens costs \$3 each, how many pens did she buy?

(1) Janel spent \$5 total.
(2) Janel bought a total of 2 pencils and pens.

hi

\$2 pencils + \$3 pens = \$5

numbers of pens and pencils cannot be any fraction, hence the answer is A
thanks

Kudos [?]: 13 [0], given: 400

Janel was shopping for pencils and pens at a Fung's Stationary Store   [#permalink] 23 Sep 2017, 23:45
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# Janel was shopping for pencils and pens at a Fung's Stationary Store

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