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marcodonzelli
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Janice is decorating her house by arranging XMas lights 31 Jan 2008, 21:48
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Janice is decorating her house by arranging XMas lights along the top of her entrance door. The XMas lights come in 5 different colors and each of the lights costs 39 cents at regular price. Janice has 2 dollars to spend on XMas lights, and she buys the lights during a holiday sale when the store gives away 1 light for every 4 purchased at the regular price. What is the maximum number of light decorations that she can create if she must use all the lights purchased?

5
60
120
360
720



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walker
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Janice is decorating her house by arranging XMas lights 31 Jan 2008, 22:18
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D

2/0.39~5
n=5+1=6

\(N=\frac{P^6_6}{P^2_2}=360\)

but really tricky for me
I had problem with understanding. Can she buy only one-color lights? Yes!
Therefore, the number of all possible light decorations have to be more than 360. But question is "maximum number after buying"...tricky
maybe I'm wrong.... :?
+1
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marcodonzelli
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Janice is decorating her house by arranging XMas lights 01 Feb 2008, 04:11
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walker
D

2/0.39~5
n=5+1=6

\(N=\frac{P^6_6}{P^2_2}=360\)

but really tricky for me
I had problem with understanding. Can she buy only one-color lights? Yes!
Therefore, the number of all possible light decorations have to be more than 360. But question is "maximum number after buying"...tricky
maybe I'm wrong.... :?
+1
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in case of repetition we have total elements!/repeating elements!, thus 6!/2!, 360. you're always right!
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jimmyjamesdonkey
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Janice is decorating her house by arranging XMas lights 01 Feb 2008, 09:52
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This problem doesn't say unique displays...it just says displays.
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maratikus
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Janice is decorating her house by arranging XMas lights 01 Feb 2008, 09:59
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marcodonzelli
Janice is decorating her house by arranging XMas lights along the top of her entrance door. The XMas lights come in 5 different colors and each of the lights costs 39 cents at regular price. Janice has 2 dollars to spend on XMas lights, and she buys the lights during a holiday sale when the store gives away 1 light for every 4 purchased at the regular price. What is the maximum number of light decorations that she can create if she must use all the lights purchased?

5
60
120
360
720
Show more

total number of lights int(200/39) = 5, plus an extra one -> 6 lights

total number of arrangements with 6 distinct lights 6!, but since there are two lights of the same color they are counted twice. the answer is 6!/2! = 720/2=360 -> D



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!