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03 Dec 2020, 01:15
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
67% (02:19) correct
33%
(02:24)
wrong
based on 210
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Not Attempted Yet
Jay and Anup can do a job, each working alone in 30 and 15 days respectively. Jay started the work and after a few days, Anup joined him. They completed the work in 18 days from the start. After how many days did Anup join A?
A. 6
B. 10
C. 12
D. 14
E. 15
A. 6
B. 10
C. 12
D. 14
E. 15
chinmayektare
Joined: 28 Nov 2018
Last visit: 18 Feb 2024
Posts: 122
Given Kudos: 34
Location: India
Concentration: General Management, Leadership
Schools: Tepper '24 (D)
GPA: 4
03 Dec 2020, 21:55
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We know ,
Jay takes 30 days to finish a work and Anup takes 15 days.
Let's take the LCM, which is 30.
Assume there are 30 units of work to be completed.
Hence, rate of doing work for Jay would be 30/30= 1 ( rate= total workdone/total timetaken)
Similarly rate of doing work for Anup would be 30/15 = 2
Let x be the number of days Jay worked for before Anup joined.
therefore , 18-x would be the days they worked together.
We know , work done = rate * time taken
SO, total work done = work done by jay + combined work done by both
i.e 30= 1*x + 3*(18-x)
Solving for x , we get x=12.
Hence Jay works for 12 days before Anup joins in.
Edit : It's my first post , hope it fits the GMAT club standard , please share some kudos if you liked it
Jay takes 30 days to finish a work and Anup takes 15 days.
Let's take the LCM, which is 30.
Assume there are 30 units of work to be completed.
Hence, rate of doing work for Jay would be 30/30= 1 ( rate= total workdone/total timetaken)
Similarly rate of doing work for Anup would be 30/15 = 2
Let x be the number of days Jay worked for before Anup joined.
therefore , 18-x would be the days they worked together.
We know , work done = rate * time taken
SO, total work done = work done by jay + combined work done by both
i.e 30= 1*x + 3*(18-x)
Solving for x , we get x=12.
Hence Jay works for 12 days before Anup joins in.
Edit : It's my first post , hope it fits the GMAT club standard , please share some kudos if you liked it
03 Dec 2020, 22:24
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CONCEPT:-Time and Work
-Total work is a sum of the individual works and the collectove work(Jay and Anup here)
SOLUTION: Let the total work be LC(15,30)=30 units.
Efficiency of Jay is 1units/day and that of Anup is 2 units/day.
Together, the efficiency is (1+2)=3 units/day
Let Jay worked for "x" days alone.
Then, 1*(x) X (18-x)*3=30
=>x=12 days (C)
Hope this helps
Devmitra Sen
-Total work is a sum of the individual works and the collectove work(Jay and Anup here)
SOLUTION: Let the total work be LC(15,30)=30 units.
Efficiency of Jay is 1units/day and that of Anup is 2 units/day.
Together, the efficiency is (1+2)=3 units/day
Let Jay worked for "x" days alone.
Then, 1*(x) X (18-x)*3=30
=>x=12 days (C)
Hope this helps
Devmitra Sen
