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15 Jul 2026, 01:10
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Here what if we do that in 8 miles per hour speed, time is 5 mins (diff between times) so we get total distance and total timw from there
15 Jul 2026, 04:19
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Bookmarks
Hi ananya88888888888,
I can see where this is coming from. You're looking at affalcon12's post, where the 5-minute gap (12 - 7) shows up, and thinking: if I also grab the 8 mph gap (48 - 40), can't I just multiply them to get the distance? It's a natural instinct, but it slips on one thing.
Why the shortcut breaks: distance = speed x time only works for one real trip - a rate you actually travel at, for a time you actually travel. But here:
- 8 mph is not a speed Jeff ever drove. It's just the gap between two averages.
- 5 minutes is not a trip time. It's the gap between two travel times.
Multiplying a speed-gap by a time-gap gives a number with no meaning. (Try it: 8 mph x 5/60 hr approximately 0.67 miles - nowhere near any answer.)
What actually makes the 5-minute idea valid: the distance is the same both days. That's why you can write
d/40 - d/48 = 5/60
The two terms are the two real travel times for the same d, and their difference is 5 minutes. Notice the 8 does appear when you combine the fractions - d/40 - d/48 = 8d/1920 - but it lives inside the structure; it's not something you multiply by 5 directly.
Quick check to feel it
Take an easy case: distance 60 miles, speeds 20 and 30 mph.
- Time at 20 = 3 hr, time at 30 = 2 hr - time gap = 1 hr
- Speed gap = 10 mph
Speed gap x time gap = 10 x 1 = 10 - but the real distance is 60. The shortcut clearly fails.
Therefore, stick with d/40 - d/48 = 5/60, which gives d = 20.
Answer: A
I can see where this is coming from. You're looking at affalcon12's post, where the 5-minute gap (12 - 7) shows up, and thinking: if I also grab the 8 mph gap (48 - 40), can't I just multiply them to get the distance? It's a natural instinct, but it slips on one thing.
Why the shortcut breaks: distance = speed x time only works for one real trip - a rate you actually travel at, for a time you actually travel. But here:
- 8 mph is not a speed Jeff ever drove. It's just the gap between two averages.
- 5 minutes is not a trip time. It's the gap between two travel times.
Multiplying a speed-gap by a time-gap gives a number with no meaning. (Try it: 8 mph x 5/60 hr approximately 0.67 miles - nowhere near any answer.)
What actually makes the 5-minute idea valid: the distance is the same both days. That's why you can write
d/40 - d/48 = 5/60
The two terms are the two real travel times for the same d, and their difference is 5 minutes. Notice the 8 does appear when you combine the fractions - d/40 - d/48 = 8d/1920 - but it lives inside the structure; it's not something you multiply by 5 directly.
Quick check to feel it
Take an easy case: distance 60 miles, speeds 20 and 30 mph.
- Time at 20 = 3 hr, time at 30 = 2 hr - time gap = 1 hr
- Speed gap = 10 mph
Speed gap x time gap = 10 x 1 = 10 - but the real distance is 60. The shortcut clearly fails.
Therefore, stick with d/40 - d/48 = 5/60, which gives d = 20.
Answer: A
ananya88888888888
16 Jul 2026, 13:41
Kudos
Bookmarks
if the distance be d,
so d(1/40 - 1/48)=(12/60 - 7/60) i.e. the gap in the delay between the two days is attributable to the gaps in the speeds on the two days
on solving d=5/60 *240=20 miles
A
so d(1/40 - 1/48)=(12/60 - 7/60) i.e. the gap in the delay between the two days is attributable to the gaps in the speeds on the two days
on solving d=5/60 *240=20 miles
A
