Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12

Question

Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow,
12 green, and 12 blue marbles. It contains no other marbles.
What is the probability that a marble chosen at random will be
either red or yellow?

A)1/6
B)1/3
C)1/2
D)2/3
E)3/4

A) 1/6
B) 1/3
C) 1/2
D) 2/3
E) 3/4

Bunuel · Answer

P(red or yellow) = (red + yellow)/(total) = (6 + 6)/(6 + 6 + 12 + 12) = 12/36 = 1/3.

Answer: B.

pushpitkc · Answer

There are a total of 6+6+12+12 or 36 marbles in Jeffrey's bag.

Therefore, the probability that the marble chosen is red or yellow is  \frac{6+6}{36}  or  \frac{1}{3}  (Option B)

akadiyan · Answer

Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow,
12 green, and 12 blue marbles. It contains no other marbles.
What is the probability that a marble chosen at random will be
either red or yellow?

A)1/6
B)1/3
C)1/2
D)2/3
E)3/4

Probability of selecting red marbles =  \frac{6}{36}  =  \frac{1}{6}

Probability of selecting Yellow marbles = \frac{6}{36}  = \frac{1}{6}

Probability of selecting yellow or red marbles = \frac{1}{6}  +  \frac{1}{6}  =  \frac{1}{3}

Ans:   B

AkshdeepS · Answer

Total marbles = 6 + 6 + 12 + 12 = 36

P (R) + P(Y) = 6/36 + 6/36 = 12/36

= 1/3

(B)

Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12

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Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12

Prep Toolkit

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