GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 16 Jan 2019, 20:50

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in January
PrevNext
SuMoTuWeThFrSa
303112345
6789101112
13141516171819
20212223242526
272829303112
Open Detailed Calendar
• ### The winning strategy for a high GRE score

January 17, 2019

January 17, 2019

08:00 AM PST

09:00 AM PST

Learn the winning strategy for a high GRE score — what do people who reach a high score do differently? We're going to share insights, tips and strategies from data we've collected from over 50,000 students who used examPAL.
• ### Free GMAT Strategy Webinar

January 19, 2019

January 19, 2019

07:00 AM PST

09:00 AM PST

Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.

# Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12

Author Message
TAGS:

### Hide Tags

Senior Manager
Joined: 02 Mar 2017
Posts: 263
Location: India
Concentration: Finance, Marketing
Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12  [#permalink]

### Show Tags

Updated on: 07 May 2017, 10:25
00:00

Difficulty:

5% (low)

Question Stats:

93% (00:48) correct 7% (00:52) wrong based on 96 sessions

### HideShow timer Statistics

Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12 green, and 12 blue marbles. It contains no other marbles. What is the probability that a marble chosen at random will be either red or yellow?

A) 1/6
B) 1/3
C) 1/2
D) 2/3
E) 3/4

_________________

Kudos-----> If my post was Helpful

Originally posted by VyshakhR1995 on 23 Apr 2017, 23:17.
Last edited by Bunuel on 07 May 2017, 10:25, edited 1 time in total.
Renamed the topic and edited the question.
Math Expert
Joined: 02 Sep 2009
Posts: 52164
Re: Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12  [#permalink]

### Show Tags

23 Apr 2017, 23:37
VyshakhR1995 wrote:
Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow,
12 green, and 12 blue marbles. It contains no other marbles.
What is the probability that a marble chosen at random will be
either red or yellow?

A)1/6
B)1/3
C)1/2
D)2/3
E)3/4

P(red or yellow) = (red + yellow)/(total) = (6 + 6)/(6 + 6 + 12 + 12) = 12/36 = 1/3.

_________________
Senior PS Moderator
Joined: 26 Feb 2016
Posts: 3334
Location: India
GPA: 3.12
Jeffrey has a bag of marbles that contains only 6 red, 6 yellow, 12 gr  [#permalink]

### Show Tags

16 May 2018, 11:09
QZ wrote:
Jeffrey has a bag of marbles that contains only 6 red, 6 yellow, 12 green, and 12 blue marbles. What is the probability that a marble at random from the bag is either red or yellow?

1. 1/6

2. 1/3

3. 1/2

4. 2/3

5. 3/4

There are a total of 6+6+12+12 or 36 marbles in Jeffrey's bag.

Therefore, the probability that the marble chosen is red or yellow is $$\frac{6+6}{36}$$ or $$\frac{1}{3}$$(Option B)

_________________

You've got what it takes, but it will take everything you've got

Senior Manager
Joined: 31 May 2017
Posts: 320
Re: Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12  [#permalink]

### Show Tags

21 May 2018, 21:04
Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12 green, and 12 blue marbles. It contains no other marbles. What is the probability that a marble chosen at random will be either red or yellow?

Probability of selecting red marbles = $$\frac{6}{36}$$ = $$\frac{1}{6}$$

Probability of selecting Yellow marbles =$$\frac{6}{36}$$ =$$\frac{1}{6}$$

Probability of selecting yellow or red marbles =$$\frac{1}{6}$$ + $$\frac{1}{6}$$ = $$\frac{1}{3}$$

Ans: B
_________________

Please give kudos if it helps

Resources
| | | | |

VP
Status: It's near - I can see.
Joined: 13 Apr 2013
Posts: 1363
Location: India
GMAT 1: 480 Q38 V22
GPA: 3.01
WE: Engineering (Consulting)
Re: Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12  [#permalink]

### Show Tags

01 Jun 2018, 22:51
VyshakhR1995 wrote:
Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12 green, and 12 blue marbles. It contains no other marbles. What is the probability that a marble chosen at random will be either red or yellow?

A) 1/6
B) 1/3
C) 1/2
D) 2/3
E) 3/4

Total marbles = 6 + 6 + 12 + 12 = 36

P (R) + P(Y) = 6/36 + 6/36 = 12/36

= 1/3

(B)

_________________

"Do not watch clock; Do what it does. KEEP GOING."

Re: Jeffrey has a bag of marbles. The bag contains 6 red, 6 yellow, 12 &nbs [#permalink] 01 Jun 2018, 22:51
Display posts from previous: Sort by