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Joan's take home pay last year was the same each month, and she saved

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Re: Joan's take home pay last year was the same each month, and she saved [#permalink]
Bunuel wrote:
Joan's take home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she saved at the end of the year was 4 times the amount of that portion of her monthly take-home pay that she did not save. If all the money that she saved last year was from her take-home pay, what percent of her take-home pay did she save each month?

A. 8.25%
B. 20%
C. 25%
D. 36%
E. 80%

In addition to the Precise methodology shown above, we'll show a method using the answers.
This is an Alternative approach and is especially helpful if you tend to get confused in long word problems.

If Joan saved 25% of her take-home pay each month, then we can say she saved x out of 4x.
Then the 'portion she didn't save' is 4x - x = 3x.
Over 12 months she would have saved x*12 = 12x.
Since 12x/3x = 4, we have our answer!

Had (C) been wrong, we would have tried (B) or (D), depending on whether the value was too small or too large.
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Re: Joan's take home pay last year was the same each month, and she saved [#permalink]
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Re: Joan's take home pay last year was the same each month, and she saved [#permalink]
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