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# Joe acquired n identical rare coins for 1,000 dollars each. Suppose th

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Math Expert
Joined: 02 Sep 2009
Posts: 52232
Joe acquired n identical rare coins for 1,000 dollars each. Suppose th  [#permalink]

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08 Jan 2018, 06:30
00:00

Difficulty:

35% (medium)

Question Stats:

73% (01:32) correct 27% (01:06) wrong based on 17 sessions

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Joe acquired n identical rare coins for 1,000 dollars each. Suppose the price at which he sells each coin is 5000 – 20n, what would his total profit be, in dollars?

A. 4,000n – 20n2
B. 5,000 – 20n2
C. 4,000 – 20n
D. (4,00 - 20n)/n
E. 5000 – 1020n

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Re: Joe acquired n identical rare coins for 1,000 dollars each. Suppose th  [#permalink]

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08 Jan 2018, 09:50
Bunuel wrote:
Joe acquired n identical rare coins for 1,000 dollars each. Suppose the price at which he sells each coin is 5000 – 20n, what would his total profit be, in dollars?

A. 4,000n – 20n2
B. 5,000 – 20n2
C. 4,000 – 20n
D. (4,00 - 20n)/n
E. 5000 – 1020n

His total cost = 1000*n
His total selling price = (5000 - 20n)*n = 5000n - 20n^2

So, his total profit = Selling price - Cost price = (5000n - 20n^2) - 1000n = 4000n - 20n^2

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Re: Joe acquired n identical rare coins for 1,000 dollars each. Suppose th  [#permalink]

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08 Jan 2018, 10:04
Bunuel wrote:
Joe acquired n identical rare coins for 1,000 dollars each. Suppose the price at which he sells each coin is 5000 – 20n, what would his total profit be, in dollars?

A. 4,000n – 20n2
B. 5,000 – 20n2
C. 4,000 – 20n
D. (4,00 - 20n)/n
E. 5000 – 1020n

Cost Price = $$1000n$$
Selling Price = $$5000n -20n^2$$

So, Profit = $$5000n -20n^2$$ - $$1000n$$

Or, Profit = $$4000n - 20n^2$$, answer will be (A)
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Re: Joe acquired n identical rare coins for 1,000 dollars each. Suppose th &nbs [#permalink] 08 Jan 2018, 10:04
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