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05 Mar 2025, 23:32
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
86% (02:06) correct
14%
(02:13)
wrong
based on 84
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John and Mike together can complete a piece of work in 18 days. After they worked together for 10 days, John stops working, and Mike completes the remaining work in 12 more days. In how many days can Mike complete the entire work alone?
(A) 28 days
(B) 27 days
(C) 24 days
(D) 22 days
(E) 20 days
(A) 28 days
(B) 27 days
(C) 24 days
(D) 22 days
(E) 20 days
05 Mar 2025, 23:37
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kingbucky
This is the following question with different numbers: https://gmatclub.com/forum/matt-and-pet ... 61130.html
05 Mar 2025, 23:59
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kingbucky
Let’s assume the total work to be 360 units.
J +M can complete a work in 18 days. Hence their efficiency together is 20 units. 360/18=20 units.
10 days of J+M work completes 20*10 = 200 units.
Remaining work is 360-200= 160 units.
Mike works for 12 days to complete 160 units of work. Therefore in one day he completes 160/12 = 40/3 units of work.
If one day Mike completes 40/3 units , therefore to complete 360 units, he takes 360/(40/3) = 27 days
Option B
Another approach
John and Mike together can complete a piece of work in 18 days. After they worked together for 10 days, John stops working, and Mike completes the remaining work in 12 more days. In how many days can Mike complete the entire work alone?
Both John and Mike complete 100% of work in 18 days.
Therefore in 10 days they complete 500/9 % of the work.
Remaining work is 100 -( 500/9)= 400/9
Mike completes 400/9 work in 12 days
Therefore , 1% of work = 12*9/(400)
100% of work =( 100*12*9)/400 =27 days. option B
